Question

我的数据如下

[['15/09/16, 12:21 pm - User1: Hey'],
 ['15/09/16, 12:22 pm - User2: <Media omitted>'],
 ["15/09/16, 12:22 pm - User2: It's yesterday's work"],
 ['15/09/16, 12:22 pm - User1: Gotta work on it.']]

我正在尝试将此嵌套列表分为日期，时间，用户名和消息的每一列。

现在我的分隔符是

,以分隔日期，

-以分隔时间，

:分隔用户名和消息

但是问题是，如果我使用:，它也会同时分隔时间，因为它的格式为XX:XX。

到目前为止，我的第一步是正确地进行分割，然后我可以继续转换为csv。

尝试1- 我尝试在读取时直接拆分数据，但是没有任何变化。

delim=",","-",":"
regexPattern = '|'.join(map(re.escape, delim))
data = []
for line in open('/content/drive/My Drive/sample.txt'):
    items = line.rstrip('\r\n').split(regexPattern)   # strip new-line characters and split on column delimiter
    items = [item.strip() for item in items]  # strip extra whitespace off data items
    data.append(items)

尝试2- 我尝试在写入csv时拆分

delim=",","-",":"
regexPattern = '|'.join(map(re.escape, delim))
with open('output.csv', 'w', newline='') as csvfile:
    writer = csv.writer(csvfile)
    re.split(regexPattern,data)
    writer.writerows(data)

这会出错，因为split需要一个字符串，并且我有一个列表。不确定如何实现我的主要目标。

感谢您的帮助。

Answer 1

使用模式handleerror

例如：

re.compile(r",|\-|\:\s+")

输出：

import re
data = [['15/09/16, 12:21 pm - User1: Hey'],
 ['15/09/16, 12:22 pm - User2: <Media omitted>'],
 ["15/09/16, 12:22 pm - User2: It's yesterday's work"],
 ['15/09/16, 12:22 pm - User1: Gotta work on it.']]


regexPattern = re.compile(r",|\-|\:\s+")
for i in data:
    for j in i:
        print(regexPattern.split(j))

使用正则表达式分组。

演示：

['15/09/16', ' 12:21 pm ', ' User1', 'Hey']
['15/09/16', ' 12:22 pm ', ' User2', '<Media omitted>']
['15/09/16', ' 12:22 pm ', ' User2', "It's yesterday's work"]
['15/09/16', ' 12:22 pm ', ' User1', 'Gotta work on it.']

输出：

import re
data = [['15/09/16, 12:21 pm - User1: Hey'],
 ['15/09/16, 12:22 pm - User2: <Media omitted>'],
 ["15/09/16, 12:22 pm - User2: It's yesterday's work"],
 ['15/09/16, 12:22 pm - User1: Gotta work on it, what,hello.']]


regexPattern = re.compile(r"(?P<date>\d{2,}\/\d{2,}\/\d{2,}),\s*(?P<time>\d{2,}:\d{2,}\s*[a-z]{2,})\s*\-\s*(?P<user>\w+)\:\s*(?P<msg>.*)$")
for i in data:
    for j in i:
        print(regexPattern.match(j).groups())

Answer 2

没有RegEx

def parse(item):
    date_time, user_message =  item.split(' - ', 1)
    return [*date_time.split(', '), *user_message.split(': ', 1)]

eggs = [['15/09/16, 12:21 pm - User1: Hey'],
        ['15/09/16, 12:22 pm - User2: <Media omitted>'],
        ["15/09/16, 12:22 pm - User2: It's yesterday's work"],
        ['15/09/16, 12:22 pm - User1: Gotta work on it.']]

spam = [parse(egg[0]) for egg in eggs]
print(spam)

输出

[['15/09/16', '12:21 pm', 'User1', 'Hey'],
 ['15/09/16', '12:22 pm', 'User2', '<Media omitted>'],
 ['15/09/16', '12:22 pm', 'User2', "It's yesterday's work"],
 ['15/09/16', '12:22 pm', 'User1', 'Gotta work on it.']]

为清楚起见，输出格式来自我本人
您需要将maxsplit明确指定为1

Answer 3

这是使用正则表达式组的完美案例。

s = '15/09/16, 12:21 pm - User1: Hey'
ms = re.match(r'(\d+/\d+/\d+).+?(\d+:\d+).+-\s(.*):\s(.*)', s)

print(ms.groups()) # ('15/09/16', '12:21', 'User1', 'Hey')

您可以将它们重新加入csv行。

嵌套列表中多个分隔符的文本为CSV（跳过首次出现）

3 个答案: