为什么此代码不输出赢家变量？

Question

我正在为我的计算机科学GCSE制作骰子游戏，并且相对较新。当尝试有条件地将新变量分配给现有变量时，代码将运行直到输出新变量并返回名称错误为止。有人可以提出任何解决方案吗？

class player:
    def __init__(self):  
        self.name = "foo"

if player1.score > player2.score:
    winner = player1.name

elif player2.score < player1.score:
    winner = player2.name

print(winner)

应该输出“ foo”，但给出名称错误：未定义名称“ winner”。

Answer 1

我想您是编码新手，否则这是一个愚蠢的错误。不用担心我来指导你

class player:
    self.name = "foo"

elif player2.score < player1.score:
    winner = player2.name

print(winner)

如果您清楚地看到自己的代码。您已经在elif中定义了赢家。这意味着它外面的代码不知道什么是“赢家”。因此，您需要在elif之外定义赢家。

winner = ''
class player:
    self.name = "foo"

elif player2.score < player1.score:
    winner = player2.name

print(winner)

Answer 2

尝试：

import random
class player:

    def __init__(self, name):
        self.name = name
        self.score = random.randint(1,6)
        print(self.name, self.score)

player_1 = player("Richard")
player_2 = player("Bob")
winner =''
if player_1.score > player_2.score:
    winner = player_1.score 
    print(winner)
elif player_2.score> player_1.score:
    winner = player_2.score 
    print(winner)
else:
    print("Tie.")

输出：