我有Tkinter程序,必须向窗口添加大量数据,所以我尝试编写for循环来处理它,但因为我必须使用字符串变量作为Tkinter的对象名称在对象上运行.insert()。我没有很好地解释这里的方法
def fillWindow(self):
global fileDirectory
location = os.path.join(fileDirectory, family + '.txt')
file = open(location, 'r')
ordersDict = {}
for line in file:
(key, value) = line.split(':', 1)
ordersDict[key] = value
for key in ordersDict:
ordersDict[key] = ordersDict[key][:-2]
for item in ordersDict:
if item[0] == '#':
if item[1] == 'o':
name = 'ordered%s' %item[2:]
这里是问题行,因为我的变量与已创建的条目对象的名称相匹配,但'name'实际上是一个字符串变量,所以它给出了错误“AttributeError:'str'对象没有属性'插入'“
name.insert(0,ordersDict[item])
这是整个班级。它创建了一个Tkinter窗口,并用一种装运屏幕填充它,所以所有条目都是需要一定数量的订单。我也很新,所以我知道我做了很多事情。
class EditShippingWindow(Tkinter.Toplevel):
def __init__(self, student):
Tkinter.Toplevel.__init__(self)
self.title('Orders')
family = student
## Window Filling
ageGroupLabel = Tkinter.Label(self,text='Age Group')
ageGroupLabel.grid(row=0,column=0)
itemColumnLabel = Tkinter.Label(self,text='Item')
itemColumnLabel.grid(row=0, column=1)
costColumnLabel = Tkinter.Label(self,text='Cost')
costColumnLabel.grid(row=0, column=2)
orderedColumnLabel = Tkinter.Label(self,text='Ordered')
orderedColumnLabel.grid(row=0, column=3)
paidColumnLabel = Tkinter.Label(self,text='Paid')
paidColumnLabel.grid(row=0, column=4)
receivedColumnLabel = Tkinter.Label(self,text='Received')
receivedColumnLabel.grid(row=0, column=5)
#Item Filling
column1list = ['T-Shirt (2T):$9.00', 'T-Shirt (3T):$9.00', 'T-Shirt (4T):$9.00',
'Praise Music CD:$10.00', ':', 'Vest L(Size 6):$10.00', 'Vest XL(Size 8):$10.00',
'Hand Book (KJ/NIV):$8.75', 'Handbook Bag:$6.00', 'Memory CD (KJ/NIV):$10.00',
':', 'Vest L(size 10):$10.00', 'Vest XL(Size 12):$10.00', 'Hand Glider (KJ/NIV/NKJ):$10.00',
'Wing Runner (KJ/NIV/NKJ):$10.00', 'Sky Stormer (KJ/NIV/NKJ):$10.00', 'Handbook Bag:$5.00',
'Memory CD (S/H/C):$10.00', 'Hand Glider Freq. Flyer:$8.00', 'Wing Runner Freq. Flyer:$8.00',
'Sky Stormer Handbook:$8.00' , ':', 'Uniform T-Shirt Size (10/12/14):$13.00',
'Uniform T-Shirt Size(10/12/14):$13.00', 'Uniform T-Shirt(Adult S / M / L / XL):$13.00',
'3rd & 4th Gr. Book 1 (KJ / NIV / NKJ):$8.75', '3rd & 4th Gr. Book 2 (KJ / NIV / NKJ):$8.75',
'4th & 5th Gr. Book 1 (KJ / NIV / NKJ):$8.75', '4th & 5th Gr. Book 2 (KJ / NIV / NKJ):$8.75',
'Memory CD 3rd & 4th Gr. Book (1/2):$10.00', 'Drawstring Backpack:$5.50']
column1num = 1
for item in column1list:
num = str(column1num)
(title, price) = item.split(':')
objectName1 = 'column1row' + num
objectName1 = Tkinter.Label(self,text=title)
objectName1.grid(row=column1num, column=1)
objectName2 = 'column1row' + num
objectName2 = Tkinter.Label(self,text=price)
objectName2.grid(row=column1num, column=2)
column1num += 1
#Ordered Paid Recieved Filler
for i in range(32):
if i == 11 or i == 22 or i == 0 or i == 5:
pass
else:
width = 10
# First Column
title1 = 'ordered' + str(i)
self.title1 = Tkinter.Entry(self,width=width)
self.title1.grid(row=i,column=3)
#self.title1.insert(0, title1)
#Second
title2 = 'paid' + str(i)
self.title2 = Tkinter.Entry(self,width=width)
self.title2.grid(row=i,column=4)
#self.title2.insert(0, title2)
#Third
title3 = 'received' + str(i)
self.title3 = Tkinter.Entry(self,width=width)
self.title3.grid(row=i,column=5)
#self.title3.insert(0, title3)
## Methods
def fillWindow(self):
global fileDirectory
location = os.path.join(fileDirectory, family + '.txt')
file = open(location, 'r')
ordersDict = {}
for line in file:
(key, value) = line.split(':', 1)
ordersDict[key] = value
for key in ordersDict:
ordersDict[key] = ordersDict[key][:-2]
for item in ordersDict:
if item[0] == '#':
if item[1] == 'o':
self.name = 'ordered%s' %item[2:]
self.name.insert(0,ordersDict[item])
fillWindow(self)
答案 0 :(得分:1)
看起来你有一个概念错误:在这个方法中,变量“name”在第一个列表的最后一行之前不存在。然后创建它,并指向一个普通的Python字符串 - 如果你在类的其他地方使用“name”变量,那么该方法中不存在变量。
要轻松修复现有代码,请尝试将变量称为“self.name”,而不仅仅是创建它的名称,并在此方法的最后一行使用:
而是self.name.insert(0,ordersDict[item])
。
self.
前缀会将您的变量转换为实例变量,该变量在类的同一实例上的方法之间共享。
另外,在这个方法中,你甚至不需要连续三次循环的字典,只需在文本变量中插入从“line”中提取的相关值。