如何在JavaScript中拆分数组以分隔后续相似项

时间:2019-05-21 07:58:27

标签: javascript jquery arrays object ecmascript-6

我有一个像这样的数组

var array = [
  {
    category: 'smart phone',
    name: 'Samsung Galaxy Note 4',
    color: 'golden',
    index: '1'
  },
  {
    category: 'smart phone',
    name: 'Qmobile Noir A10',
    color: 'white',
    index: '2'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy note 8',
    color: 'black',
    index: '3'
  },
  {
    category: 'laptop',
    name: 'Dell inspiron n5110',
    color: 'black',
    index: '4'
  },
  {
    category: 'laptop',
    name: 'Macbook Pro',
    color: 'golden',
    index: '5'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy S5',
    color: 'white',
    index: '6'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy S3',
    color: 'white',
    index: '7'
  },
];

,并希望根据并发的相似项目进行拆分。为此,如果我应用过滤器。

array.filter(item => item.category === 'smart phone');

它不仅提供并发项目,而且还过滤掉“智能手机”类别下的所有项目。

arr1 = [
  {
    category: 'smart phone',
    name: 'Samsung Galaxy Note 4',
    color: 'golden',
    index: '1'
  },
  {
    category: 'smart phone',
    name: 'Qmobile Noir A10',
    color: 'white',
    index: '2'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy note 8',
    color: 'black',
    index: '3'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy S5',
    color: 'white',
    index: '6'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy S3',
    color: 'white',
    index: '7'
  },
];

我想要达到的目标是这样的。

// output required
// concurrent items of smartphone category
arr1 = [
  {
    category: 'smart phone',
    name: 'Samsung Galaxy Note 4',
    color: 'golden',
    index: '1'
  },
  {
    category: 'smart phone',
    name: 'Qmobile Noir A10',
    color: 'white',
    index: '2'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy note 8',
    color: 'black',
    index: '3'
  },
];

// concurrent items of laptop category
arr2 = [
  {
    category: 'laptop',
    name: 'Dell inspiron n5110',
    color: 'black',
    index: '4'
  },
  {
    category: 'laptop',
    name: 'Macbook Pro',
    color: 'golden',
    index: '5'
  },
];

// again concurrent items of smartphone category
arr3 = [
  {
    category: 'smart phone',
    name: 'Samsung Galaxy S5',
    color: 'white',
    index: '6'
  },
  {
    category: 'smart phone',
    name: 'Samsung Galaxy S3',
    color: 'white',
    index: '7'
  },
];

如何在JavaScript / jQuery中获得此结果。

4 个答案:

答案 0 :(得分:2)

您可以减少数组并采用新的数组来更改类别。

结果是一个数组数组,其中每个数组按原始顺序具有相同的类别。

var array = [{ category: 'smart phone', name: 'Samsung Galaxy Note 4', color: 'golden', index: '1' }, { category: 'smart phone', name: 'Qmobile Noir A10', color: 'white', index: '2' }, { category: 'smart phone', name: 'Samsung Galaxy note 8', color: 'black', index: '3' }, { category: 'laptop', name: 'Dell inspiron n5110', color: 'black', index: '4' }, { category: 'laptop', name: 'Macbook Pro', color: 'golden', index: '5' }, { category: 'smart phone', name: 'Samsung Galaxy S5', color: 'white', index: '6' }, { category: 'smart phone', name: 'Samsung Galaxy S3', color: 'white', index: '7' }],
    result = array.reduce((r, o, i, { [i - 1]: last = {} }) => {
        if (last.category !== o.category) r.push([]);
        r[r.length - 1].push(o);
        return r;
    }, []);

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

答案 1 :(得分:2)

您可以使用reduce对对象进行分组。创建一个变量以跟踪先前的category是什么。如果它与当前category相同,则将对象推到累加器的最后一个数组。否则,将一个新数组推入累加器。

const array=[{category:'smart phone',name:'Samsung Galaxy Note 4',color:'golden',index:'1'},{category:'smart phone',name:'Qmobile Noir A10',color:'white',index:'2'},{category:'smart phone',name:'Samsung Galaxy note 8',color:'black',index:'3'},{category:'laptop',name:'Dell inspiron n5110',color:'black',index:'4'},{category:'laptop',name:'Macbook Pro',color:'golden',index:'5'},{category:'smart phone',name:'Samsung Galaxy S5',color:'white',index:'6'},{category:'smart phone',name:'Samsung Galaxy S3',color:'white',index:'7'},];

let previous;

const output = array.reduce((acc, o) => {
  if (previous !== o.category) {
    previous = o.category
    acc.push([o])
  } else {
    acc[acc.length - 1].push(o)
  }
  
  return acc;
}, [])

console.log(output)

答案 2 :(得分:1)

您可以这样做,将reduceslice结合使用并进行解构:

var array = [{category:'smart phone',name:'Samsung Galaxy Note 4',color:'golden',index:'1'},{category:'smart phone',name:'Qmobile Noir A10',color:'white',index:'2'},{category:'smart phone',name:'Samsung Galaxy note 8',color:'black',index:'3'},{category:'laptop',name:'Dell inspiron n5110',color:'black',index:'4'},{category:'laptop',name:'Macbook Pro',color:'golden',index:'5'},{category:'smart phone',name:'Samsung Galaxy S5',color:'white',index:'6'},{category:'smart phone',name:'Samsung Galaxy S3',color:'white',index:'7'}];
const [[arr1, arr2, arr3]] = array.reduce(([acc, cat], curr) => {
  curr.category == cat ? acc[acc.length - 1].push(curr) : acc.push([curr]);
  return [acc, curr.category];
}, [[]]).slice(0, -1);
console.log(arr1);
console.log(arr2);
console.log(arr3);
.as-console-wrapper { max-height: 100% !important; top: auto; }

答案 3 :(得分:0)

请确保:您需要分配.filter()

的输出
let filteredArray = array.filter(item => item.category === 'smart phone');

仅写array.filter(your function)不会改变array