如何为“ 404未找到”创建自定义响应消息？

Question

如果get请求接受具有字母值的jobCategoryId，我想用我的自定义消息创建404 Not Found错误响应。

请求格式：

GET /JobProfilesByCategory/:jobCategoryId

views.py：

class JobProfilesByCategoryView(generics.ListAPIView):    
"""
    A custom view to create a view for Job profile by Category. Lookup_url_kwarg fetches the jobCategoryId variable from the URL 
"""
model=JobProfiles
serializer_class = JobProfilesByCategorySerializer
lookup_url_kwarg = "jobCategoryId"

def get_queryset(self):
    jobCategoryId = self.kwargs.get(self.lookup_url_kwarg)
    print(jobCategoryId)
    if(any(c.isalpha() for c in jobCategoryId)):
        return Response({"detail":"Not Found"},status=status.HTTP_404_NOT_FOUND)
    else:
        queryset = JobProfiles.objects.filter(jobCategoryId=jobCategoryId)
        return queryset

urls.py：

    url(r'JobProfilesByCategory/(?P<jobCategoryId>[-\w]+$)',view=views.JobProfilesByCategoryView.as_view()),#6th API

Answer 1

您可以使用NotFound

from rest_framework.exceptions import NotFound
...
def get_queryset(self):
    jobCategoryId = self.kwargs.get(self.lookup_url_kwarg)
    print(jobCategoryId)
    if (any(c.isalpha() for c in jobCategoryId)):
        raise NotFound({"custom_key": "Custom Error Message"})
    else:
        queryset = JobProfiles.objects.filter(jobCategoryId=jobCategoryId)
        return queryset