Question

我为动态链接挣扎了好几天。请感谢任何帮助。我集成了Firebase动态链接，如果我将链接粘贴到Chrome网址中，然后按Enter，它可以打开事件触发并传递了网址的应用但是如果我单击预览页面上的“打开”按钮，则无论是否安装了该应用程序，它始终会打开App Store 有什么想法吗？

我浏览了网络上的所有帖子，但没有好运。

"react-native": "^0.59.5"
"react-native-firebase": "^5.3.1"

pod 'Firebase/Core', '~> 5.20.1'
pod 'Firebase/DynamicLinks', '~> 5.20.1'

在Firebase控制台上的域：https://links.umrgo.com/links

捆绑ID：com.umrgo.www.umr-app-ios

URL Types identifier: links.umrgo.com
URL Types identifier: com.umrgo.www.umr-app-ios


capabilities: applinks:links.umrgo.com

发布版本

我还用字符串数组添加FirebaseDynamicLinksCustomDomains https://links.umrgo.com

我的一些代码如下。

   [FIROptions defaultOptions].deepLinkURLScheme = @"com.umrgo.www.umr-app-ios";

- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url
            options:(NSDictionary<NSString*, id> *)options
{
  BOOL handled = [[RNFirebaseLinks instance]
                  application:application
                  openURL:url
                  options:options
                  ] || [RCTLinkingManager
                        application:application
                        openURL:url
                        options:options
                        ];

  return handled;
}

- (BOOL)application:(UIApplication *)application
continueUserActivity:(NSUserActivity *)userActivity
 restorationHandler:(void (^)(NSArray *))restorationHandler {
  BOOL handled = [[RNFirebaseLinks instance]
                  application:application
                  continueUserActivity:userActivity
                  restorationHandler:restorationHandler
                  ] || [RCTLinkingManager
                        application:application
                        continueUserActivity:userActivity
                        restorationHandler:restorationHandler
                        ];

  return handled;
}

- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url
  sourceApplication:(NSString *)sourceApplication annotation:(id)annotation
{
  BOOL handled = [RCTLinkingManager
                  application:application
                  openURL:url
                  sourceApplication:sourceApplication
                  annotation:annotation
                  ];
  return handled;
}


const link = new firebase.links.DynamicLink(`https://www.umrgo.com/publish/${publishId}?publishType=${publishType}&publishId=${publishId}&otherUserUnionId=${currentUserUnionId}&conversationId=${conversationId}`,
        'links.umrgo.com/links').android.setPackageName(conf.GooglePackageName).ios.setBundleId(conf.AppleBundleId).ios.setAppStoreId(conf.AppleAppID);

firebase.links()
    .createShortDynamicLink(link, 'UNGUESSABLE')
    .then((url) => {
        var payload = {
            key: createLinkUniqueKey(conversationId, publishId, currentUserUnionId, publishType),
            url: url,
            publish_id: publishId,
            target_user_unionid: currentUserUnionId,
            conversation_id: conversationId,
            publish_type: publishType
        }
        axios.post(getApiEndpoint(conf.UMRApiUrls.createDynamicLinkRemote), payload, {
            headers: getAuthHeader()
        }).then(response => {
            console(response)
        })
    });

下面是一些快照：

redirect to app store

ask for open app

enter link in browser and press enter

app open with url passed if enter link in browser

bottom right is the app, release build

Answer 1

您提到将链接粘贴到浏览器中。如果您在 Safari 中执行此操作，它会故意不直接转到您的应用程序，因为设备会假设您的意图是打开网页。如果您点击链接，它的行为可能会有所不同。 Chrome 可能也在遵循同样的想法。

这个答案提供了一些很好的测试步骤来确保它正常工作：https://stackoverflow.com/a/44817701/2612222

无论是否安装了App，动态链接始终会打开App Store

1 个答案: