我正在尝试使用for循环将数据插入数据库中,并且似乎代码中没有错误,因为编译器不会提示任何错误,但是当我单击“提交”按钮时,未插入数据
我只尝试了mysqli,因为它是我最熟悉的
$db = mysqli_connect('localhost','root','','generator');
$statement = mysqli_query($db, 'SELECT LAST_INSERT_ID()');
$order_id = mysqli_fetch_array($statement);
for($count=0; $count<$_POST["total_item"]; $count++)
{
$statement = $db->prepare("
INSERT INTO docgenitem
(order_id, vendor, itemdescription, order_item_quantity, order_item_price, order_item_actual_amount )
VALUES (:order_id, :vendor, itemdescription, :order_item_quantity, :order_item_price, :order_item_actual_amount)
");
$statement->execute(
array(
':order_id' => $order_id,
':vendor' => trim($_POST["item_name"][$count]),
':itemdescription' => trim($_POST["itemdescription"][$count]),
':quantity' => trim($_POST["order_item_quantity"][$count]),
':priceperunit' => trim($_POST["order_item_price"][$count]),
':amount' => trim($_POST["order_item_final_amount"][$count]),
)
);
}
答案 0 :(得分:0)
您的代码应为:
$db = new mysqli('localhost','root','','generator');
$order_id = $db->insert_id;
for($count=0; $count<$_POST["total_item"]; $count++)
{
$s1 = trim($_POST["item_name"][$count]);
$s2 = trim($_POST["itemdescription"][$count]);
$s3 = trim($_POST["order_item_quantity"][$count]);
$s4 = trim($_POST["order_item_price"][$count]);
$s5 = trim($_POST["order_item_final_amount"][$count]);
$statement = $db->prepare("
INSERT INTO docgenitem
(order_id, vendor, itemdescription, order_item_quantity, order_item_price, order_item_actual_amount )
VALUES (?, ?, ?, ?, ?, ?)
");
$statement->bind_param('dsssss', $order_id, $s1, $s2, $s3, $s4, $s5);
$statement->execute();
}
$statement->close();
$db->close();