租金是具有所有已注册租金的表格,其中开始日期和结束日期为属性。查询后,我只想获得此productGroups,其中的某些产品在给定的时间段内(“已过滤” obj)没有租金冲突。
我认为我只需要添加(以某种方式)具有空的“出租”属性的条件。与产品属性相同。
有人知道如何得到这个吗?
ProductGroup有很多产品
产品有很多租赁
filtered.startDate,filtered.endDate是新租期的开始和结束日期
ProductGroup.findAll({
include: [
{
model: Product,
include: [
{
model: Rentals,
where: {
[Op.or]: [
{
startDate: {
[Op.between]: [filtered.startDate, filtered.endDate]
}
},
{
endDate: {
[Op.between]: [filtered.startDate, filtered.endDate]
}
}]
},
required: false
}
],
required: true
}
]
})
型号:
module.exports = function(sequelize, DataTypes) {
let productGroups = sequelize.define('productGroups', {
id: {
type: DataTypes.INTEGER(11),
allowNull: false,
primaryKey: true,
autoIncrement: true,
field: 'ID'
},
name: {
type: DataTypes.STRING(255),
allowNull: false,
unique: true,
field: 'name'
}
}, {
timestamps: false,
tableName: 'product_groups'
});
productGroups.associate = ( models ) =>{
productGroups.hasMany( models.product, { foreignKey: 'productGroupId', sourceKey: 'id' } );
};
return productGroups;
};
module.exports = function(sequelize, DataTypes) {
let product = sequelize.define('product', {
id: {
type: DataTypes.INTEGER(11),
allowNull: false,
primaryKey: true,
autoIncrement: true,
field: 'ID'
},
name: {
type: DataTypes.STRING(255),
allowNull: false,
field: 'name'
},
productGroupId: {
type: DataTypes.INTEGER(11),
allowNull: false,
references: {
model: 'product_groups',
key: 'ID'
},
field: 'product_group'
}
}, {
timestamps: false,
tableName: 'product'
});
product.associate = ( models ) =>{
product.belongsTo( models.productGroups, { foreignKey: 'productGroupId', targetKey: 'id' } );
product.hasMany( models.rentals, { foreignKey: 'productId', sourceKey: 'id' } );
};
return product;
};
module.exports = function(sequelize, DataTypes) {
let rentals = sequelize.define('rentals', {
id: {
type: DataTypes.INTEGER(11),
allowNull: false,
primaryKey: true,
autoIncrement: true,
field: 'ID'
},
startDate: {
type: DataTypes.DATEONLY,
allowNull: false,
field: 'start_date'
},
endDate: {
type: DataTypes.DATEONLY,
allowNull: false,
field: 'end_date'
},
productId: {
type: DataTypes.INTEGER(11),
allowNull: false,
references: {
model: 'product',
key: 'ID'
},
field: 'product_id'
}
}, {
timestamps: false,
tableName: 'rentals'
});
rentals.associate = ( models ) =>{
rentals.belongsTo( models.product, { foreignKey: 'productId', targetKey: 'id' } );
};
return rentals;
};
样本过滤参数:
filtered = {
startDate: 2019-05-20,
endDate: 2019-05-29,
} //dates are date objects
样本表:
product_groups = [
{ID: 1, name: 'test1'},
{ID: 2, name: 'test2'}
]
product = [
{ID: 1, name: 'prod1', product_group: 1},
{ID: 2, name: 'prod2', product_group: 1},
{ID: 3, name: 'prod3', product_group: 2},
{ID: 4, name: 'prod4', product_group: 1},
]
rentals = [
{ID: 1, start_date: 2017-10-01, end_date: 2017-10-25, product_id: 1},
{ID: 2, start_date: 2019-05-27, end_date: 2019-05-31, product_id: 1},
{ID: 3, start_date: 2018-10-12, end_date: 2018-10-14, product_id: 2},
{ID: 4, start_date: 2019-05-10, end_date: 2019-06-31, product_id: 3}
] //dates are date objects
因此,我希望只有具有某些可用产品的productGroups, 产品的可用性取决于租金(如果产品的租金与提供的“过滤的” obj相冲突,则不退还)
在此示例中,我只希望ID = 1的ProductGroup和ID = [2、4]的产品
答案 0 :(得分:0)
尝试在产品级别添加where子句:
where: {
'$rental_table_name.primary_key$' : { [Op.eq]: null }
},
(适当替换表名和PK)。
更新的解决方案:
在“产品组”部分尝试以下操作:
where: {
'$products.rentals.ID$' : { [Op.eq]: null }
},