Question

以起始编号= 13，上限= 112，step_size = 3运行程序只要数字继续打印数字

我已尝试将其拆分并使用break失败完成此任务。

public class Bounds {  
    public static void main(String[] args) {

        int startingNumber;
        int upperBound = 112;
        int stepSize =3;
        int count =0;

        Scanner input = new Scanner(System.in);
        System.out.println("Enter starting number: ");
        startingNumber=input.nextInt();

        System.out.println("Enter upper bound number");
        upperBound = input.nextInt();

        System.out.print(startingNumber + " ");

        System.out.print(" ");

        while (startingNumber <= upperBound) {

            System.out.print((startingNumber += stepSize) + " ");

            if ((count%10) == 0)
                count += 3;

            System.out.print( " ");

            input.close();
        }
    }
}

Answer 1

太复杂了，使用for循环怎么办

public static void main(String[] args) {
    int startingNumber;
    int upperBound = 112;
    int stepSize =3;
    int count =0;

    Scanner input = new Scanner(System.in);
    System.out.println("Enter starting number: ");
    startingNumber = input.nextInt();

    System.out.println("Enter upper bound number");
    upperBound = input.nextInt();

    int range = upperBound - startingNumber;
    for (int i = startingNumber; i < upperBound; i+=stepSize) {
        System.out.println(i);
        count++;
                }
    System.out.println("done: count value: "+count);

}

Answer 2

您对以下内容有什么想法？

         if ((count%10) == 0)
                count += 3;

因此，仅在余数为零时才递增计数。那只会工作一次。但是您还要采取什么其他措施？也许您是想做这样的事情。

         count += 3;
         if ((count%10 == 0) {
               System.out.println();
         }

如何将数字分成多行？

2 个答案: