Question

我有一个包含两列的数据集。我想将其中一列分类为bin，然后将每个bin中另一列中的值求和。

我尝试了以下代码

select DISTINCT (
     CASE WHEN H=1 THEN '1'
     WHEN H BETWEEN 2 AND 3 THEN '2-3' 
     WHEN H BETWEEN 4 AND 6 THEN '4-6'
     ELSE '' END
) AS H , sum(V) [V]
from
  TABLE1 inner join TABLE 2 on TABLE1.X=TABLE2.X
where 
  TABLE.X=1 and Y='id' 
GROUP BY H
ORDER BY H ASC

下表提供了我的数据示例（其中H和V为标题）

H      V
1      100
1      1000
1      1500
2      300
3      500
4      9000
5       800
6      1100

我想要的输出是

H          V
1          2600
2 TO 3     800
4 TO 6     10900

但是，我正在获取（即重复的bin，因为未将V列的值合并到每个bin中的所有值中）

Answer 1

您似乎想要聚合计算列：

select (CASE WHEN H = 1 THEN '1'
             WHEN H BETWEEN 2 AND 3 THEN '2-3'
             WHEN H BETWEEN 4 AND 6 THEN '4-6'
             ELSE ''
        END) AS H , sum(V) as V
from TABLE1 inner join
     TABLE2
     on TABLE1.X = TABLE2.X
where TABLE.X = 1 and Y = 'id'
GROUP BY (CASE WHEN H = 1 THEN '1'
               WHEN H BETWEEN 2 AND 3 THEN '2-3'
               WHEN H BETWEEN 4 AND 6 THEN '4-6'
               ELSE ''
          END)
ORDER BY MIN(H) ASC;

您应该限定查询中的所有列引用。

SELECT DISTINCT几乎永远不适用于GROUP BY。

SQL中带有求和值的语句的情况

1 个答案: