Question

如何使用Groovy将DATETIME类型的数据从2018-12-14 14:16:58.037967格式化为2018-12-14T14:16:58.037967？

程序：

import java.time.LocalDateTime
import java.time.format.DateTimeFormatter

def DB_formattime = LocalDateTime.parse("2019-05-18 20:54:04.638314", DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.n"))

print DB_formattime

错误：

Caught: java.time.format.DateTimeParseException: Text '2019-05-18 20:54:04.638314' could not be parsed at index 10
java.time.format.DateTimeParseException: Text '2019-05-18 20:54:04.638314' could not be parsed at index 10
    at java_time_LocalDateTime$parse.call(Unknown Source)
    at test.run(test.groovy:4)

Process finished with exit code 1

Answer 1

这里最简单的方法就是用'T'字符代替空格...

"2018-12-14 14:16:58.037967".tr(' ','T')

但是，如果您想解析和格式化日期，则：

import java.time.LocalDateTime 
import java.time.format.DateTimeFormatter

def DB_formattime = LocalDateTime.parse("2019-05-18 20:54:04.638314", DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.n"))
DB_formattime.format(DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.n"))

如何使用Groovy将DATETIME类型的数据从“ 2018-12-14T14：16：58.037967”格式化为“ 2018-12-14 14：16：58.037967”？

1 个答案: