我正在使用电话号码texfield,现在我在texfield中使用这种格式(#)### ### ###,现在的问题是我希望将第一个字符0强制性化,例如(0)959 554 545,因此用户输入的任何第一个字符都必须输入0,
这是我的代码
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
let newString = textField.text
if ((newString == "") && (newString?.count == 0)){
txtMobileNumber.text = "0"
return true
}else if ((newString?.count)! > 0){
return true
}
return false
}
答案 0 :(得分:2)
在shouldChangeCharactersIn
的{{1}}方法中,
UITextFieldDelegate
每次编辑func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
if let text = textField.text {
let str = (text as NSString).replacingCharacters(in: range, with: string).replacingOccurrences(of: "(0)", with: "")
if !str.isEmpty {
textField.text = "(0)" + str
} else {
textField.text = nil
}
}
return false
}
时,将(0)
附加到新创建的string
。
答案 1 :(得分:1)
在shouldChangeCharactersIn
方法中,如果新字符串数大于15,则返回false。否则,请删除(0)
并保留空格,然后,如果字符串不为空,请在开头添加(0)
。然后将字符串每3个字符分割一次,并用空格分隔符将所有字符串连接起来。
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
var oldText = (textField.text! as NSString).replacingCharacters(in: range, with: string)
if oldText.count > 15 { return false }
oldText = oldText.replacingOccurrences(of: "(0)", with: "").replacingOccurrences(of: " ", with: "")
if !oldText.isEmpty {
oldText = "(0)" + oldText
}
let newText = String(stride(from: 0, to: oldText.count, by: 3).map {
let sIndex = String.Index(encodedOffset: $0)
let eIndex = oldText.index(sIndex, offsetBy: 3, limitedBy: oldText.endIndex) ?? oldText.endIndex
return String(oldText[sIndex..<eIndex])
}.joined(separator: " "))
textField.text = newText
return false
}
答案 2 :(得分:1)
如果创建枚举,则可以选择textField类型并为此字段设置扩展名属性
func textField(_ textField: UITextField,
shouldChangeCharactersIn range: NSRange,
replacementString string: String) -> Bool {
if cellType == .phone {
guard var sanitizedText = textField.text else { return true }
if !sanitizedText.isEmpty && !sanitizedText.hasPrefix("(0)") {
sanitizedText.text = "(0)" + sanitizedText
}
}
}