Question

我想显示由逗号分隔的链接项目列表，最后一个项目除外。我似乎语法不正确

<?php  $prerequisite = get_field('prerequisites'); ?>
<?php if( $prerequisite ):  ?>
    <li> Prerequisites: 

    <?php foreach( $prerequisite as $prerequisites ): ?>

    <a href="<?php echo get_permalink( $prerequisites->ID ); ?>"><?php echo get_the_title($prerequisites->ID ); ?></a>
    <?php endforeach; ?>

    </li>

<?php endif; ?>

Answer 1

尝试此代码

使用 trim 函数逗号分隔值管理，您可以在此处找到 trim 函数详细信息：https://www.w3schools.com/php/func_string_trim.asp

<?php 
$prerequisite = get_field('prerequisites');
if( $prerequisite ):  
  ?>
  <li> Prerequisites: 
  <?php 
  $nvtest = "";
  foreach( $prerequisite as $prerequisites ): 
      $nvtest.='<a href="'.get_permalink( $prerequisites->ID ).'">'.get_the_title($prerequisites->ID ).'</a> ,';
  endforeach; 
  echo trim($nvtest," ,");
  ?>
  </li>
<?php endif; ?>

如何用逗号将ACF数组内插

1 个答案: