Question

我有一个ajax脚本，该脚本以与以往相同的方式调用Web方法，但是现在无法获得响应。我解析错误。请帮忙。

[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public void UzmiTaskove(int idprojekta)
{
        List<Taskovi> listataskova = new List<Taskovi>();
        string CS = Properties.Settings.Default.Konekcija.ToString();

        using (SqlConnection con = new SqlConnection(CS))
        {
            SqlCommand cmd4 = new SqlCommand("UzmiTaskove", con);
            cmd4.CommandType = CommandType.StoredProcedure;

            con.Open();

            cmd4.Parameters.AddWithValue("@IdProj", idprojekta);

            SqlDataReader rdr = cmd4.ExecuteReader();

            while (rdr.Read())
            {
                Taskovi tas = new Taskovi();
                tas.ID = Convert.ToInt32(rdr["ID"]);
                tas.IdProjekta = Convert.ToInt32(rdr["IdProjekta"]);
                tas.Opis = rdr["Opis"].ToString();
                tas.DatumPocetka = rdr["DatumPocetka"].ToString();
                tas.DatumZavrsetka = rdr["DatumZavrsetka"].ToString();
                tas.Status = rdr["Status"].ToString();

                listataskova.Add(tas);
            }
        }

        JavaScriptSerializer jm = new JavaScriptSerializer();
        Context.Response.Write(jm.Serialize(listataskova));
}

$.ajax({
        url: 'TaskoviServis.asmx/UzmiTaskove',
        type: 'POST',
        data:JSON.stringify({ idprojekta:idprojekta}),
        dataType: 'json',
        contentType: "application/json; charset=utf-8",

        success: function (respons) {
            alert(respons.d);

            var newHtml = "";
            $(poda).each(function (index, tas) {

                newHtml += '<li class="task">';
                newHtml += '<div class="task-container">';
                newHtml += '<span class="task-action-btn task-check">';
                newHtml += '<span class="action-circle large complete-btn" title="Mark Complete">';
                newHtml += '<i class="material-icons">check</i>';
                newHtml += '</span>';
                newHtml += '</span>';
                newHtml += '<span class="task-label" contenteditable="true">' + tas.Opis + '</span>';
                newHtml += '<span class="task-action-btn task-btn-right">';
                newHtml += '<span class="action-circle large" title="Assign">';
                newHtml += '<i class="material-icons">person_add</i>';
                newHtml += '</span>';
                newHtml += '<span class="action-circle large delete-btn" title="Delete Task">';
                newHtml += '<i class="material-icons">delete</i>';
                newHtml += '</span>';
                newHtml += '</span>';
                newHtml += '</div>';
                newHtml += '</li>';
            });

            $("#task-list").append(newHtml);
        },
        error: function (xhr, textStatus, error) {
            console.log(xhr.statusText);
            console.log(textStatus);
            console.log(error);
        }
    });

我尽了一切..更改数据类型..等等...

Answer 1

好了，这个方法给您带来了麻烦，因为它使问题无处不在，所以在ajax代码中什么都不要更改，只要更改webmethod代码的make返回类型和返回值而不是response.write，直接更改ajax代码就可以了。 / p>

[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public List<Taskovi> UzmiTaskove(int idprojekta)
{
        List<Taskovi> listataskova = new List<Taskovi>();
        string CS = Properties.Settings.Default.Konekcija.ToString();

        using (SqlConnection con = new SqlConnection(CS))
        {
            SqlCommand cmd4 = new SqlCommand("UzmiTaskove", con);
            cmd4.CommandType = CommandType.StoredProcedure;

            con.Open();

            cmd4.Parameters.AddWithValue("@IdProj", idprojekta);

            SqlDataReader rdr = cmd4.ExecuteReader();

            while (rdr.Read())
            {
                Taskovi tas = new Taskovi();
                tas.ID = Convert.ToInt32(rdr["ID"]);
                tas.IdProjekta = Convert.ToInt32(rdr["IdProjekta"]);
                tas.Opis = rdr["Opis"].ToString();
                tas.DatumPocetka = rdr["DatumPocetka"].ToString();
                tas.DatumZavrsetka = rdr["DatumZavrsetka"].ToString();
                tas.Status = rdr["Status"].ToString();

                listataskova.Add(tas);
            }
        }

       // JavaScriptSerializer jm = new JavaScriptSerializer();
      //  Context.Response.Write(jm.Serialize(listataskova));
      return listataskova;
}

并在ajax中进行如下更改

$.ajax({
    url: 'TaskoviServis.asmx/UzmiTaskove',
    type: 'POST',
    data:JSON.stringify({ idprojekta:idprojekta}),
    dataType: 'json',
    contentType: "application/json; charset=utf-8",

    success: function (respons) {
        //alert(respons.d);
        console.log(respons.d)
        var newHtml = "";
        $(respons.d).each(function (index, tas) {

            newHtml += '<li class="task">';
            newHtml += '<div class="task-container">';
            newHtml += '<span class="task-action-btn task-check">';
            newHtml += '<span class="action-circle large complete-btn" title="Mark Complete">';
            newHtml += '<i class="material-icons">check</i>';
            newHtml += '</span>';
            newHtml += '</span>';
            newHtml += '<span class="task-label" contenteditable="true">' + tas.Opis + '</span>';
            newHtml += '<span class="task-action-btn task-btn-right">';
            newHtml += '<span class="action-circle large" title="Assign">';
            newHtml += '<i class="material-icons">person_add</i>';
            newHtml += '</span>';
            newHtml += '<span class="action-circle large delete-btn" title="Delete Task">';
            newHtml += '<i class="material-icons">delete</i>';
            newHtml += '</span>';
            newHtml += '</span>';
            newHtml += '</div>';
            newHtml += '</li>';
        });

        $("#task-list").append(newHtml);
    },
    error: function (xhr, textStatus, error) {
        console.log(xhr.statusText);
        console.log(textStatus);
        console.log(error);
    }
});

尝试这应该可行。

如何从webmethod获得响应并传递sql参数

1 个答案: