Vec <t>的Option :: take（）等效于什么？

Question

struct A {
    pub v: Vec<i32>
}

fn extract(a: &mut A) -> Vec<i32> {
    let res = a.v.clone(); // TODO: move out of a.v
    res
}

如何在Vec<T>结构内移出&mut？

这是How can I swap in a new value for a field in a mutable reference to a structure?

的副本