Question

我正在编写一个游戏代码，其中计算机从1到100中选择一个随机数，然后玩家必须弄清楚数字是多少。当您猜数字时，系统会告诉您数字是高还是低。

当您猜到数字时，应该打印一条消息，说您猜对了，此后它应该中断。当您猜到数字时，它会完全跳过打印功能并中断。

我什么都没尝试过，因为我不知道该怎么做。我在编程方面还很陌生。

代码如下：

import random
num = random.randint(1, 100)
guess = int(input("Guess which number I chose from 1 to 100: "))

while guess != num:
    if guess > num:
        print ("That number is too high")
        guess = int(input("Guess which number I chose from 1 to 100: "))
    elif guess < num:
        print ("That number is too low")
        guess = int(input("Guess which number I chose from 1 to 100: "))
    elif guess == num:
        print ("You guessed it! Want to play again?")
        option = input("Press Y for yes or N for no: ")
        if option.lower() == "y":
            guess = int(input("Guess which number I chose from 1 to 100: "))
        elif option.lower() == "n":
            break
        else:
            print ("Not valid")
            break

没有错误消息。找到号码后，代码就会中断。

Answer 1

看看while循环中的情况

while guess != num:

因为您在循环结束时读取了猜测，所以在得到猜测之后，代码将立即检查while条件。因此，当您猜测正确时，while条件将失败，并退出循环。由于您已经休息了，可以通过将其更改为

来解决此问题

while True:

Answer 2

尝试此代码。可行，我改变了条件。

import random
num = random.randint(1, 100)
guess = int(input("Guess which number I chose from 1 to 100: "))
option = 'y'
while (option.lower() == 'y'):
    if guess > num:
        print ("That number is too high")
        guess = int(input("Guess which number I chose from 1 to 100: "))
    elif guess < num:
        print ("That number is too low")
        guess = int(input("Guess which number I chose from 1 to 100: "))
    else:
        print ("You guessed it! Want to play again?")
        option = input("Press Y for yes or N for no: ")
        if option.lower() == 'y':
            guess = int(input("Guess which number I chose from 1 to 100: "))
        elif option.lower() == 'n':
            break
        else:
            print ("Not valid")
            break

代码跳过print（）函数，直接中断

2 个答案: