那是我拥有api函数的控制器:
public function loginsub(Request $request)
{
$credentials = $request->only('email', 'password');
if(Auth::guard('sub_users')->attempt($credentials))
{
$user = Auth::guard('sub_users');
}
}
来自auth.php
配置的卫兵和提供者:我已经编辑了帖子并添加了提供者部分
'guards' => [
'web' => [
'driver' => 'session',
'provider' => 'users',
],
'api' => [
'driver' => 'passport',
'provider' => 'users',
],
'sub_users' => [
'driver' => 'passport',
'provider' => 'sub_users'
],
],
'providers' => [
'users' => [
'driver' => 'eloquent',
'model' => App\User::class,
],
'sub_users' => [
'driver' => 'eloquent',
'model' => App\sub_users::class,
],
],
我收到此错误:
“消息”:“方法尝试不存在。”, “状态码”:500
我正在尝试使用子用户模型登录:
<?php
namespace App;
use Laravel\Passport\HasApiTokens;
use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;
class sub_users extends Authenticatable
{
use HasApiTokens, Notifiable;
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'name', 'email', 'password','type','login_ip',
];
/**
* The attributes that should be hidden for arrays.
*
* @var array
*/
protected $hidden = [
'password', 'remember_token',
];
}
我也尝试了check()
而不是尝试,但没有用
预先感谢
答案 0 :(得分:1)
公共功能loginsub(Request $ request) { $ credentials = $ request-> only('email','password');
if(Auth::guard('users')->attempt($credentials))
{
$user = Auth::guard('users');
}
}