Question

即时通讯使用Mysql 5.1并使用列customerid付款，付款日期我需要所有客户的最新付款。所以带有条目的表

row, customerid, paymentdate
1    5           2011-03-01
2    5           2011-04-01
3    6           2011-01-01
4    7           2011-01-01
5    7           2011-02-01

应该返回2,3,5行查询

select max(paymentdate),customerid from payments where customerid=5;

我试图进入某种WHERE客户IN（...），但没有运气，因为它返回2列不仅1

感谢

最后答案激发了我找到相关信息并解决了问题以下查询（如文章评论中所述）

select * from (select * from payments order by paymentdate desc) as p group by customerid;

same problem from mysql forum solutions from a related mysql article

Answer 1

您应该group by customerid。

select max(paymentdate),customerid from payments group by customerid;

Answer 2

另一种方法：

Select paymentdate,customerid from payments group by customerid order by paymentdate DESC;

甚至：

Select distinct(customerid),paymentdate from payments order by paymentdate DESC;

按顺序添加DESC会导致首先返回最近的日期。

SQL：获取所有客户的最新付款？

2 个答案: