Question

我的日期为“ 08/08/2019”，我希望它看起来像这样：“ 08，Aug 2019”，我尝试使用<?php //Assume this line is correct and that you have a database.php file containing your log in credientials include 'database.php'; //If Statement says - run this next piece of code if $_POST['query'] is set to something if (isset($_POST['query'])) { // $search_query = $_POST['query']; - Commented OUT //This line attempts to sanatise the input from the posted data $search_query = mysqli_real_escape_string($_POST["query"]); //This line constructs the whole SQL statement ( BAd methodology here, but thats a different topic) $query = "SELECT * FROM transporter WHERE email LIKE '%" . $search_query . "%' LIMIT 12"; //You've commented out the next line and its of no use // $query = "SELECT * FROM transporter WHERE address LIKE %' //This line has a syntax error - but is also of no use - Should delete but should read $search_query = ' LIMIT 12'; //$search_query ' LIMIT 12"; /// This line queries the database $result = mysqli_query($link, $query); //This line declares $data will be an array $data = array(); //If the DB returns some rows if (mysqli_num_rows($result) > 0) { // While there are results while ($row = mysqli_fetch_assoc($result)) { //add to the $data array $data[] = $row["email"]; } //Output $data in JSON format to be interpreted as a response from your ajax call echo json_encode($data); } } ?>，但想知道是否有更简便的方法？我知道这是一个很小的问题，但是我试图在互联网上找到答案，但找不到。

Answer 1

首先，您需要将字符串转换为Date对象，然后使用新的java.time

将其转换为您的格式

更新

val firstDate = "08/08/2019"
val formatter = DateTimeFormatter.ofPattern("dd/MM/yyyy")
val date = formatter.parse(firstDate)
val desiredFormat = DateTimeFormatter.ofPattern("dd, MMM yyyy").format(date)
println(desiredFormat) //08, Aug 2019

旧答案

val firstDate = "08/08/2019"
val formatter = SimpleDateFormat("dd/MM/yyyy")
val date = formatter.parse(firstDate)
val desiredFormat = SimpleDateFormat("dd, MMM yyyy").format(date)
println(desiredFormat) //08, Aug 2019

Answer 2

使用预定义的本地化格式和java.time

    Locale englishIsrael = Locale.forLanguageTag("en-IL");
    DateTimeFormatter shortDateFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.SHORT)
            .withLocale(englishIsrael);
    DateTimeFormatter mediumDateFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.MEDIUM)
            .withLocale(englishIsrael);

    String dateStringWeHave = "08/08/2019";
    LocalDate date = LocalDate.parse(dateStringWeHave, shortDateFormatter);
    String dateStringWeWant = date.format(mediumDateFormatter);
    System.out.println(dateStringWeWant);

很抱歉，Java语法值得翻译。输出为：

2019年8月8日

与您要求的08, Aug 2019并不完全相同。但是，Java通常对全球人们期望的格式有一个很好的主意，因此我的第一个建议是您考虑使用该格式（坦白说08，逗号对我来说也有些奇怪，但是我知道什么？？）

代码段演示的另一个功能是使用Java.time（现代Java日期和时间API）中的LocalDate和DateTimeFormatter。我热烈建议在诸如Date尤其是SimpleDateFormat这样过长的日期时间类上使用java.time。他们的设计很差。替换它们是有原因的。

如果用户说他们绝对想要08, Aug 2019，则需要通过格式模式字符串来指定：

    DateTimeFormatter handBuiltFormatter = DateTimeFormatter.ofPattern("dd, MMM uuuu", englishIsrael);
    String dateStringWeWant = date.format(handBuiltFormatter);

现在，我们确实获得了您要求的输出：

08，2019年8月

链接： Oracle tutorial: Date Time解释了如何使用Java.time（现代Java日期和时间API）。

Answer 3

您可以使用Java的SimpleDataFormat类：

import java.text.SimpleDateFormat

代码中的某处：

val myDateStr = "08/08/2019"
val parsedDateObj = SimpleDateFromat("dd/MM/yyyy").parse(myDateStr)
val formattedDateStr = SimpleDateFormat("dd, MMM yyyy").format(parsedDateObj) // "08, Aug 2019"

将日期月份格式化为3个首字母的字符串-Kotlin

3 个答案:

使用预定义的本地化格式和java.time