如何使用loadash / javascript嵌套多个groupby

时间:2019-05-19 02:12:47

标签: javascript arrays object ecmascript-6 lodash

预先感谢任何可以帮助我的人。我正在尝试在React Native中使用SectionList显示数据。我在下面显示了我要完成的工作的代码。常规的javascript解决方案将起作用。我希望首先按日期将数据分组,然后在该日期之内按位置将它们分组。

具有标题和数据键很重要 我有这种格式的数据:

[ { game_id: 1171,
    date: '2018-11-17',
    location: 'Plaza'
   },
  { game_id: 1189,
    date: '2018-11-17',
    location: 'Field - Kickball'
   },
   { game_id: 1489,
    date: '2018-11-16',
    location: 'Field - Kickball'
   },
   { game_id: 1488,
    date: '2018-11-16',
    location: 'Field - Soccer'
   }
]

我需要显示输出:

data = [{
    title: "2018-11-17",
    data: [{
            title: "Field - Kickball",
            data: [{
                game_id: 1189,
                date: '2018-11-17',
                location: 'Field - Kickball'
            }]
        },
        {
            title: "Plaza",
            data: [{
                game_id: 1171,
                date: '2018-11-17',
                location: 'Plaza'
            }]
        }
    ]
    },
    {
        title: "2018-11-16",
        data: [{
                title: "Field - Kickball",
                data: [{
                    game_id: 1489,
                    date: '2018-11-16',
                    location: 'Field - Kickball'
                }]
            },
            {
                title: "Field - Soccer",
                data: [{
                    game_id: 1488,
                    date: '2018-11-16',
                    location: 'Field - Soccer'
                }]
            }
        ]
    }
]

我已经尝试过了

const games = [data here]
var groups = _(games)
.groupBy(x => x.date)
        .map(value => {
            return _.groupBy(value, 'location')
            .map(({key, value}) => ({title: key, data: value}))
        })

        .map((value, key) => {
            return ({title: value[Object.keys(value)[0]][0].date, data: value})
        })

2 个答案:

答案 0 :(得分:1)

像这样使用reduce

const data = [{game_id:1171,date:'2016-11-17T05:00:00.000Z',time:'08:00:00',category:'Ch B Coed',background:'#FFFF00',textcolor:'#000000',bold:0,sport:'Newcomb',location:'Plaza',text:'COL2 vs. USA1 1171'},{game_id:1189,date:'2016-11-17T05:00:00.000Z',time:'08:50:00',category:'Ch A Coed',background:'#FF33CC',textcolor:'#000000',bold:0,sport:'Kickball',location:'Field - Kickball',text:'COL1 vs. USA1 1189'},{game_id:1489,date:'2016-2-17T05:00:00.000Z',time:'04:50:00',category:'Ch B Coed',background:'#FF33CC',textcolor:'#000000',bold:0,sport:'Kickball',location:'Field - Kickball',text:'COL2 vs. USA3 1489'}];

const res = Object.values(data.reduce((acc, { date, ...rest }) => acc[date] ? { ...acc, [date]: { ...acc[date], data: acc[date].data.concat({ date, ...rest })} } : { ...acc, [date]: { title: date, data: [{ date, ...rest }] }}, {}));

console.log(res);
.as-console-wrapper { max-height: 100% !important; top: auto; }

答案 1 :(得分:0)

如果我缺少什么,请原谅我,但这似乎可以通过Array.reduce以某种更简单的方式完成:

let data = [{ game_id: 1171, date: '2016-11-17T05:00:00.000Z', time: '08:00:00', category: 'Ch B Coed', background: '#FFFF00', textcolor: '#000000', bold: 0, sport: 'Newcomb', location: 'Plaza', text: 'COL2 vs. USA1 1171' }, { game_id: 1189, date: '2016-11-17T05:00:00.000Z', time: '08:50:00', category: 'Ch A Coed', background: '#FF33CC', textcolor: '#000000', bold: 0, sport: 'Kickball', location: 'Field - Kickball', text: 'COL1 vs. USA1 1189' }, { game_id: 1489, date: '2016-2-17T05:00:00.000Z', time: '04:50:00', category: 'Ch B Coed', background: '#FF33CC', textcolor: '#000000', bold: 0, sport: 'Kickball', location: 'Field - Kickball', text: 'COL2 vs. USA3 1489' } ]

let result = data.reduce((r, c) => {
  r[c.date] = r[c.date] || {title: c.date, data: []}
  r[c.date].data = [...(r[c.date].data || []), c]
  return r
}, {})

console.log(Object.values(result))