我有一个数据框,其中某些字符串在字符串的开头和结尾都包含“”。
例如:
+-------------------------------+
|data |
+-------------------------------+
|"john belushi" |
|"john mnunjnj" |
|"nmnj tyhng" |
|"John b-e_lushi" |
|"john belushi's book" |
预期输出:
+-------------------------------+
|data |
+-------------------------------+
|john belushi |
|john mnunjnj |
|nmnj tyhng |
|John b-e_lushi |
|john belushi's book |
我正在尝试仅删除字符串中的双引号。有人可以告诉我如何在Scala中删除它吗?
Python提供ltrim和rtrim。有什么与Scala中的功能等效的吗?
答案 0 :(得分:4)
使用 expr,子字符串和 length 函数并从2
和length() - 2
val df_d = List("\"john belushi\"", "\"John b-e_lushi\"", "\"john belushi's book\"")
.toDF("data")
Input:
+---------------------+
|data |
+---------------------+
|"john belushi" |
|"John b-e_lushi" |
|"john belushi's book"|
+---------------------+
Using expr, substring and length functions:
import org.apache.spark.sql.functions.expr
df_d.withColumn("data", expr("substring(data, 2, length(data) - 2)"))
.show(false)
Output:
+-------------------+
|data |
+-------------------+
|john belushi |
|John b-e_lushi |
|john belushi's book|
+-------------------+
答案 1 :(得分:2)
如何从字符串Scala的开头和结尾删除引号?
myString.substring(1, myString.length()-1)
将删除双引号。
import spark.implicits._
val list = List("\"hi\"", "\"I am learning scala\"", "\"pls\"", "\"help\"").toDF()
list.show(false)
val finaldf = list.map {
row => {
val stringdoublequotestoberemoved = row.getAs[String]("value")
stringdoublequotestoberemoved.substring(1, stringdoublequotestoberemoved.length() - 1)
}
}
finaldf.show(false)
结果:
+--------------------+
| value|
+--------------------+
| "hi"|
|"I am learning sc...|
| "pls"|
| "help"|
+--------------------+
+-------------------+
| value|
+-------------------+
| hi|
|I am learning scala|
| pls|
| help|
+-------------------+
答案 2 :(得分:2)
尝试
Number