Retrofit2方法未处理

时间:2019-05-18 20:31:38

标签: android retrofit retrofit2 dagger

我正在开发一个简单的气象应用程序,并尝试通过改造来提取数据。我正在调试代码。

compositedisposable.add(apiservi by ..... 在这里,在调试的第36行“变量不可用”中写入和停止时,我无法提取数据。

-> newConsumer ...显示以下建议。

“匿名新使用者(Ctrl + F1) 检查信息:报告所有匿名类 Java 1.7或更早版本的JVM不支持Lambda语法。 “

如果您想查看GithubLink:https://github.com/rumtblbl/LocationWeatherApp

请帮助我,谢谢。 WeatherCityNameServiceImp.java

    package com.example.locationweatherapp.Data.Network.Service;

import android.view.View;
import android.widget.Toast;

import com.example.locationweatherapp.Data.Network.ApiClient;
import com.example.locationweatherapp.Data.Network.ApiInterface;
import com.example.locationweatherapp.Data.Network.Model.WeatherResult;
import com.example.locationweatherapp.Utility.Utils;
import com.squareup.picasso.Picasso;


import javax.inject.Inject;

import io.reactivex.android.schedulers.AndroidSchedulers;
import io.reactivex.disposables.CompositeDisposable;
import io.reactivex.functions.Consumer;
import io.reactivex.schedulers.Schedulers;


public class WeatherCityNameServiceImp implements WeatherCityNameService {

    private ApiInterface apiService;
    CompositeDisposable compositeDisposable;

    @Inject
    public WeatherCityNameServiceImp() {
        apiService = ApiClient.getClient().create(ApiInterface.class);
        compositeDisposable = new CompositeDisposable();
    }


    @Override
    public void weatherCityNameService(String cityName, final ServiceCallBack<WeatherResult> callBack) {

        compositeDisposable.add(apiService.weatherCityNameService(cityName, Utils.APP_ID, "metric")
                .subscribeOn(Schedulers.io())
                .observeOn(AndroidSchedulers.mainThread())
                .subscribe(new Consumer<WeatherResult>() {
                    @Override
                    public void accept(WeatherResult weatherResult) throws Exception {
                        callBack.onResponse(weatherResult);
                    }
                }, new Consumer<Throwable>() {
                    @Override
                    public void accept(Throwable throwable) throws Exception {
                        callBack.onError(throwable.getMessage());
                    }
                })

        );


    }
}

0 个答案:

没有答案