在单独的android进程上启动服务无法正常工作

Question

我想在一个单独的过程中启动服务，但是什么也没发生（当使用相同的过程时，它起作用了，烤面包了。）

Android清单：

        <service
            android:name=".DelayedToastIntentService"
            android:enabled="true"
            android:exported="false"
            android:process=":delayed_toast">
        </service>

MainActivity：

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        intentService = new Intent(MainActivity.this, DelayedToastIntentService.class);
        r1 = new Receiver("r1");
        IntentFilter filter = new IntentFilter();
        filter.addAction("toast");        LocalBroadcastManager.getInstance(this).registerReceiver(r1, filter);
        editText = (EditText) findViewById(R.id.editText);
    }
    private class Receiver extends BroadcastReceiver {
        @Override
        public void onReceive(Context context, Intent intent) {
            Toast.makeText(getApplicationContext(), "Délai écoulé : " + String.valueOf(intent.getIntExtra("period",0)),
                    Toast.LENGTH_LONG).show();
        }
    }
    public void onStartDelayedToast(View v){     intentService.putExtra("period",Integer.valueOf(String.valueOf(editText.getText())));
        intentService.setAction("toast");
        startService(intentService);
    }

DelayedToastIntentService：

    public class DelayedToastIntentService extends IntentService {
    @Override
    protected void onHandleIntent(@Nullable Intent intent) {
        final int period =intent.getIntExtra("period",10);
        SystemClock.sleep(period*1000);        LocalBroadcastManager.getInstance(getApplicationContext()).sendBroadcast(intent);
    }
}