正则表达式，用于匹配具有4至6位数字ID的URL

Question

我正在尝试匹配以"example.com/"开头，后跟4-6位数字且下一个字符不是数字（如果有下一个字符）的URL。

例如，"example.com/12345"应该匹配。

"example.com/1234567"应该不匹配。

"example.com/123456g7"应该匹配。

我尝试过"example.com/(\d{4,6}).*"，但是当我给它"example.com/1234567"时，这是不正确的。

如何解决此问题？

Answer 1

另一种方法。

^example\.com/(\d{4,6})(?:\D.*)?$

Answer 2

此表达式添加了其他边界，只是为了安全地传递所需的URL：

^(https?:\/\/(www.)?)(example\.com)\/(?:[0-9]{4,6})?([a-z].*)?$

如果愿意，可以缩小界限。在这里，我们可以添加几个捕获组以简化调用。

$是使您不希望的URL输入失败的键。

RegEx

如果这不是您想要的表达式，则可以在regex101.com中修改/更改表达式。

RegEx电路

您还可以在jex.im中可视化您的表达式：

JavaScript演示

const regex = /^(https?:\/\/(www.)?)(example\.com)\/(?:[0-9]{4,6})?([a-z].*)?$/gm;
const str = `http://example.com/12345
https://example.com/123456g7
http://www.example.com/12345
https://www.example.com/123456g7
http://www.example.com/12345
https://www.example.com/123456g7
http://www.example.com/123456adfasdfasdf98989898
https://www.example.com/123456g7adfadfa0909009
http://example.com/1234567
https://example.com/1234567`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

Python测试

# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility

import re

regex = r"^(https?:\/\/(www.)?)(example\.com)\/(?:[0-9]{4,6})?([a-z].*)?$"

test_str = ("http://example.com/12345\n"
    "https://example.com/123456g7\n"
    "http://www.example.com/12345\n"
    "https://www.example.com/123456g7\n"
    "http://www.example.com/12345\n"
    "https://www.example.com/123456g7\n"
    "http://www.example.com/123456adfasdfasdf98989898\n"
    "https://www.example.com/123456g7adfadfa0909009\n"
    "http://example.com/1234567\n"
    "https://example.com/1234567")

matches = re.finditer(regex, test_str, re.MULTILINE)

for matchNum, match in enumerate(matches, start=1):

    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

    for groupNum in range(0, len(match.groups())):
        groupNum = groupNum + 1

        print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.

Answer 3

在匹配4到6位数字后，对数字进行正负查找：

example.com\/\d{4,6}(?!\d).*

https://regex101.com/r/YWmhgY/1/