Question

我有一个视频文件，想通过套接字发送。视频已发送到客户端，但视频无法播放，并且接收到的视频大小为2 KB。视频大小最大为43 MB。问题是什么？帮我！这是我的代码。

服务器：

import socket

try:

    soc = socket.socket()
    print('socked created.')
    host = ''
    port = 8080

    soc.bind((host, port))
    print('soc bound.')

    soc.listen(10)
    print('waiting for connecting...')

    con, addr = soc.accept()
    print('server connected to IP: ' + addr[0] + " port: " + str(addr[1]))

    while True:

        filename = input('enter filename: ')
        file = open(filename, 'rb')
        sendfile = file.read(9000000)
        con.send(sendfile)
        print("file has been send.")
        break

    con.close()
    soc.close()

except socket.error as err:
    print('error ', str(err))

客户端：

import socket

soc = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print('socked created. waiting for connecting to server...')

server_address = ("192.168.1.3", 8080)

soc.connect(server_address)
print('connected to the server.')

while True:
    recvfile = soc.recv(9000000)
    savefilebyname = input("enter file name: ")
    openfile = open(savefilebyname, 'wb')
    openfile.write(recvfile)
    openfile.close()
    break

print("File has been received.")

soc.close()

Answer 1

检查send和recv的返回值。 9000000值是最大值，但不能保证发送/接收的值。或者，使用sendall。

对于recv，您必须循环播放，直到收到所有数据为止。如果在文件发送后关闭套接字，则recv将在收到所有数据后返回零。

仅供参考，两个文件中的while True:永远不会由于break而循环播放，因此它们是不必要的。

这里应该起作用...

server.py

import socket

soc = socket.socket()
soc.bind(('',8080))
soc.listen(1)

print('waiting for connection...')
with soc:
    con,addr = soc.accept()
    print('server connected to',addr)
    with con:
        filename = input('enter filename to send: ')
        with open(filename, 'rb') as file:
            sendfile = file.read()
        con.sendall(sendfile)
        print('file sent')

client.py

import socket

soc = socket.socket()
soc.connect(('localhost',8080))
savefilename = input("enter file name to receive: ")
with soc,open(savefilename,'wb') as file:
    while True:
        recvfile = soc.recv(4096)
        if not recvfile: break
        file.write(recvfile)
print("File has been received.")

python通过套接字发送大文件（发送video.mp4文件）

1 个答案: