大家好,我是MongoDB的初学者。我想在mongodb中返回一些文档。我正在使用NodeJS。我的集合中有多个文档。以我为例,我想返回具有名为make 2002和2008的列的文档,并且我只需要名称为return的列。谢谢。...
My code:
db.collection('cars').find(
{$and:[ {$in:{make:{2002,2008}} ]}
,{name:1,_id:0},(err,doc)=>{
if(err){
throw err;
}
else{
console.log(doc);
}});
I have collections in my db:
/* 1 */
{
"_id" : ObjectId("5cddda829719b0234ccef10d"),
"name" : "Posche",
"make" : 2002,
"price" : 2300000
}
/* 2 */
{
"_id" : ObjectId("5cdee01d1f92122b785874ba"),
"name" : "Audi",
"make" : 2002,
"price" : 2300000
}
/* 3 */
{
"_id" : ObjectId("5cdee01d1f92122b785874bb"),
"name" : "BMW",
"make" : 2003,
"price" : 2000000
}
/* 4 */
{
"_id" : ObjectId("5cdee01d1f92122b785874bc"),
"name" : "Toyoto",
"make" : 2005,
"price" : 1500000
}
/* 5 */
{
"_id" : ObjectId("5cdee3e71f0e0ab8a16cb2c8"),
"make" : 2008,
"name" : "Volvo",
"price" : 59862
}
My Expected output:
[{"name" : "Posche"},
{"name" : "Audi"},
{"name" : "volvo"}]
答案 0 :(得分:2)
您似乎要查找的查询是:
carry = 0
...其余代码
这将返回db.collection('cars').find({ make: {$in:[2002,2008]},{name:1,_id:0},
与前两年匹配的文档。