Question

我第一次使用django制作Rest API，我在该项目的网站上制作了该教程，但现在我对此表示怀疑，也没有找到明确的答案。

我正在制作的API具有基本终结点（例如：api.site.com/v1/videos/）和其他依赖于嵌套配置的终结点（例如：api.site.com/v1/videos/<pk:video>/label/<pk:label>）。

但是我正在使用视图集HyperlinkedModelViewSet和Rest框架中的模式。

所有嵌套结构都具有指向根端点的外键。因此，“标签”模型具有来自类别的外键。一个类别可以有多个标签。

这是我实际正在使用的代码：

urls.py

from django.urls import path, include
from rest_framework import DefaultRouter
from API import views
from rest_framework.schemas import get_schema_view

# Create a router and register our viewsets with it.
router = DefaultRouter()
router.register(r'users', views.UserViewSet)
router.register(r'videos', views.VideoViewSet)
router.register(r'categories', views.CategoryVieWSet)

schema_view = get_schema_view(title='Annotation Tool API')

# The API URLs are now determined automatically by the router.
urlpatterns = [
    path('', include(router.urls)),
    path('schema/', schema_view),
]

views.py

from API.models import User, Video, Category
from API.serializers import UserAPISerializer, VideoSerializer, CategorySerializer
from rest_framework import generics
from rest_framework import permissions
from rest_framework.decorators import api_view
from rest_framework.decorators import action
from rest_framework.response import Response
from rest_framework.reverse import reverse
from rest_framework import renderers
from rest_framework import viewsets

class UserViewSet(viewsets.ModelViewSet):

    queryset = User.objects.all()
    serializer_class = UserAPISerializer

class VideoViewSet(viewsets.ModelViewSet):

    queryset = Video.objects.all()
    serializer_class = VideoSerializer

class CategoryVieWSet(viewsets.ModelViewSet):

    queryset = Category.objects.all()
    serializer_class = CategorySerializer

serializers.py

from rest_framework import serializers
from API.models import User, Video, Category, Label, Track, Annotation, Comment
from django.contrib.auth.models import User as djangoUser

class UserAPISerializer(serializers.HyperlinkedModelSerializer):

    class Meta:
        model = User
        fields = ('id', 'email', 'nickname', 'access', 'created_at',
                'updated_at', 'deleted_at',
                'usr_created', 'usr_updated', 'usr_deleted')

class VideoSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = Video
        fields = ('id', 'extid', 'access', 'created_at', 'updated_at', 'deleted_at', 
                'created_by', 'updated_by', 'deleted_by')

class CategorySerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = Category
        fields = ('id', 'name', 'access', 'created_at', 'updated_at', 'deleted_at',
                'created_by', 'updated_by', 'deleted_by', 'description', 'has_duration',
                'settings', 'video')

我希望像这样调用“标签”端点：

显示所需类别的所有标签/创建新标签：api.site.com/v1/categories/<category:pk>/labels/

仅显示指定的标签/更新指定的标签： api.site.com/v1/categories/<category:pk>/labels/<label:pk>

如何使用HyperlinkedModel和Schema实现该目标，或者应使用其他策略？如果还有其他麻烦的策略（例如使用ModelView或mixins），是否可以与我现在使用的策略混合？

HyperlinkedModelViewSet +模式：如何制作嵌套的URL？

urls.py

views.py

serializers.py

0 个答案: