当我尝试创建带有类别api的新啤酒时,我有一个关系,其中一个表名为“ 类别”,另一个表名为“ Beer ”错误。
BeerController
/**
* @Route("/", methods={"POST"})
* @param Request $request
* @return Response
*/
public function saveAction(Request $request){
$data_arr = json_decode($data = $request->getContent(),true);
$beer = new Beer();
$category = new Category();
$beer->getCategory();
$form = $this->createForm(BeerType::class, $beer);
$form->submit($data_arr);
$beer->setCategory($category);
$doctrine = $this->getDoctrine()->getManager();
$doctrine->persist($category);
$doctrine->merge($beer);
$doctrine->flush();
return new JsonResponse([$data_arr], 200);
}
啤酒实体
/**
* Beer
*
* @ORM\Table(name="beers")
* @ORM\Entity
*/
class Beer
{
/**
* @ORM\ManyToOne(targetEntity="AppBundle\Entity\Category", inversedBy="beer", cascade={"persist", "remove" }))
* @ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
private $category;
/**
* @return mixed
*/
public function getCategory()
{
return $this->category;
}
/**
* @param mixed $category
*/
public function setCategory($category)
{
$this->category = $category;
}
}
CategoryEntity
class Category
{
/**
* @ORM\OneToMany(targetEntity="AppBundle\Entity\Beer", mappedBy="category")
*/
private $beer;
public function __construct()
{
$this->beer = new ArrayCollection();
}
}
啤酒类型(窗体)
class BeerType extends AbstractType
{
/**
* {@inheritdoc}
*/
public function buildForm(FormBuilderInterface $builder, array
$options)
{
$builder->add('name')
->add('description')
->add('price')
->add('slug')
->add('type')
->add('abv')
->add('brewedby')
->add('createdat')
->add('updatedat')
->add('category', EntityType::class, [
'class' => Category::class
])
;
console.log(错误)
”执行'INSERT INTO类别(名称)时发生异常 带有参数[null]的VALUES(?)' SQLSTATE [23000]:违反完整性约束:1048列“名称” 不能为空”
正如问题本身所言,当我尝试创建具有类别(已创建)的新啤酒时,控制器尝试创建新类别,但是我想创建具有已创建类别的新啤酒。
编辑:
当我通过api从啤酒中发送数据时,类别正常发送,但是当我尝试用get推送啤酒时,类别就没有更多的啤酒了。
张贴啤酒
{abv: 7, brewedby: "Péttrin Miranda Souza", category_id: "7", description: "Descrição da cerva",…}
abv: 7
brewedby: "Péttrin Miranda Souza"
category_id: "7"
description: "Descrição da cerva"
name: "Beer"
price: "25"
slug: "mugger"
type: "Cerveja bavaria"
喝啤酒
5: {id: 19, name: "Beer", description: "Descrição da cerva", price: 25, slug: "mugger",…}
abv: 7
brewedby: "Péttrin Miranda Souza"
createdat: "2019-05-20T09:28:08-03:00"
description: "Descrição da cerva"
id: 19
name: "Beer"
price: 25
slug: "mugger"
type: "Cerveja bavaria"
updatedat: "2019-05-20T09:28:08-03:00"
答案 0 :(得分:1)
由于您已经在表单中选择了类别实体,因此无需实例化类别实体或将其持久化(遇到的错误来自创建新实例并持久化-而不是使用现有类别在表单数据绑定中连接到啤酒实体的引用)。您可以尝试以下操作版本:
/**
* @Route("/", methods={"POST"})
* @param Request $request
* @return Response
*/
public function saveAction(Request $request){
$doctrine = $this->getDoctrine()->getManager();
$data_arr = json_decode($data = $request->getContent(),true);
$beer = new Beer();
$form = $this->createForm(BeerType::class, $beer);
$form->submit($data_arr);
$category = $doctrine->getRepository(Category::class)->find($data_arr['category_id']);
$beer->setCategory($category);
$doctrine->persist($beer);
$doctrine->flush();
return new JsonResponse([$data_arr], 200);
}
在附加评论后更新了答案。因此,现在根据给定的参数ID明确获取类别。另一个解决方案-以前的简单控制器代码没有对类别进行任何特殊提取-将使用表单数据转换器(symfony data transormer),该数据转换器将int id自动映射到类别对象。