Question

我有一个tableview，在这里我从名为PlaylistArray的数组中加载了所有详细信息。我有一个搜索页面，用户可以从playlistArray中搜索类型为[[String: Any]]的。我不知道如何过滤用户在PlayListArray到filteredArray中给出的搜索文本。我已附上PlaylistArray答复，以供您参考。

这是我之前尝试过滤PlaylistArray的代码。

 let searchPredicate = NSPredicate(format: "SELF CONTAINS[c] %@", searchController.searchBar.text!)
 let array = (constantsList.playTypeArray.lectureArraymp3 as NSArray).filtered(using: searchPredicate)
          //  filtered_Array.add(array)
 print(array)

我需要搜索用户提供的搜索文本，我们必须将搜索文本与title的{{1}}标签进行比较。当两者相同时，我需要向过滤后的数组显示特定数组索引的全部细节。

PlaylistArray：

playlistArray

Answer 1

这是使用filter API的快速解决方案。在此处详细了解：https://developer.apple.com/documentation/swift/sequence/3018365-filter

let array = [["title": "Kaṭha-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png"],
             ["title": "Kaṭa-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://www.imaginetventures.name/swamijione/wp-content/uploads/2019/01/gitanew.png"]]

guard let searchText = searchController.searchBar.text else {return} //Or use if-let
let filteredArray = array.filter { (object) -> Bool in
    guard let title = object["title"] as? String else {return false}
    return title?.contains(searchText) ?? false
}

Answer 2

不是使用字典数组，而是使用结构数组。创建一个结构和结构实例

//Item
struct Item {
    var title: String
    var imageUrl: URL
    var mp3Url: URL
    init?(details: [String:Any]) {
        if let title = details["title"] as? String,
            let imageStr = details["image_url"] as? String,
            let imageUrl = URL(string: imageStr),
            let mp3Str = details["mp3"] as? String,
            let mp3Url = URL(string: mp3Str) {
                self.title = title
                self.imageUrl = imageUrl
                self.mp3Url = mp3Url
        } else { return nil }
    }
}

然后使用title属性过滤数组。

let playlistArray = [["title": "Kaṭha-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://...", "mp3": "https://..."],
                     ["title": "Kaṭha-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://...", "mp3": "https://..."],
                     ["title": "Kaṭha-Bhāṣyam-41 Mantra 1-2-20", "image_url": "https://...", "mp3": "https://..."]]
let playlistArr = playlistArray.compactMap(Item.init)
print(playlistArr)
let searchText = "Kar"//searchController.searchBar.text!
let filteredArray = playlistArr.filter({ $0.title.localizedCaseInsensitiveContains(searchText) })
print(filteredArray)

搜索过滤器必须从[[String：Any]]（）数组过滤到新的过滤数组？

2 个答案: