Question

我要将多个字典添加到列表中，然后将其转换为json。它给了我多个列表，每个列表增加了一个额外的结果。我想将整个输出显示在列表的单个数组中。

mail_output = []

for i in mail_ids.split():
    result, msg_data = mail.fetch(i, '(RFC822)')

    for each_response in msg_data:
        if isinstance(each_response, tuple):
            msg = email.message_from_string(each_response[1])                  
            items_list = msg.items()
            dict_items = OrderedDict(items_list)       
            email_body = ''
            if msg.is_multipart():
                for part in msg.walk():
                    case...
            dict_items.update({'Body': email_body})
    mail_output.append(dict_items)

    print(json.dumps(mail_output, indent=4, sort_keys=True))

我得到的输出：

[
 {
  "Body": "Forwarded.\r\n\r\nFrom: User
  "Subject": "Fw: Tuesday", 
  "To": "<reciever@gmail.com>"
 }
]
[
 {
  "Body": "Forwarded.\r\n\r\nFrom: User
  "Subject": "Fw: Tuesday", 
  "To": "<reciever@gmail.com>"
 },
 {
  "Body": "Urgent Message.\r\n\r\nFrom: Alerts
  "Subject": "Alerts", 
  "To": "<reciever@gmail.com>"
 }
]

预期输出：

[
 {
  "Body": "Forwarded.\r\n\r\nFrom: User
  "Subject": "Fw: Tuesday", 
  "To": "<reciever@gmail.com>"
 },
 {
  "Body": "Urgent Message.\r\n\r\nFrom: Alerts
  "Subject": "Alerts", 
  "To": "<reciever@gmail.com>"
 }
 .....
]

Answer 1

mail_output = []

for i in mail_ids.split():
    result, msg_data = mail.fetch(i, '(RFC822)')

    for each_response in msg_data:
        if isinstance(each_response, tuple):
            msg = email.message_from_string(each_response[1])                  
            items_list = msg.items()
            dict_items = OrderedDict(items_list)       
            email_body = ''
            if msg.is_multipart():
                for part in msg.walk():
                    case...
            dict_items.update({'Body': email_body})
    mail_output.append(dict_items)

print(json.dumps(mail_output, indent=4, sort_keys=True))

您只是遇到缩进问题。.请参阅此处的最后一行..这是我更改的唯一部分。否则，脚本将为for i in mail_ids.split()的每次迭代打印。

将多个字典附加到列表中并转储到json中

1 个答案: