Question

我有2个数组。第一个是我的数组，第二个是API响应：

$array1 = [
    ["id" => 45, "name" => "toto"],
    ["id" => 50, "name" => "tata"],
    ["id" => 31, "name" => "titi"],
    ["id" => 82, "name" => "tutu"],
    ["id" => 12, "name" => "tototo"]
];

$array2 = [
    "45" => ["status" => false], 
    "50" => ["status" => true], 
    "31" => ["status" => true],
    "82" => ["status" => false],
    "12" => ["status" => true]
];

我想在array1中删除id中状态为array2的所有false，或将所有id保持状态为{{1 }}

在此示例中，我需要获取：

true

由于$array1 = [ ["id" => 50, "name" => "tata"], ["id" => 31, "name" => "titi"], ["id" => 12, "name" => "tototo"] ]; id和45在第二个数组中为假，因此我将它们从第一个数组中删除。

如何在不使用多个循环的情况下做到这一点？如果我们使用诸如82之类的php函数或类似的方法，有解决方案？

Answer 1

您可以使用import imp some_module = imp.load_source('some_module', '/path/to/some_module.py')来过滤array_filter。如果$array1存在并且状态为true，则返回true。

id

这将导致：

$array1 = ...
$array2 = ...

$result = array_filter($array1, function( $o ) use( $array2 ) {
    return isset( $array2[ $o["id"] ] ) && $array2[ $o["id"] ]["status"];
});

Answer 2

最具可读性的解决方案通常比使用精美的array_*函数要好，也就是说，在这种情况下，简单的foreach循环就足够了：

https://3v4l.org/5eNEf

<?php

$array1 = [
    ["id" => 45, "name" => "toto"],
    ["id" => 50, "name" => "tata"],
    ["id" => 31, "name" => "titi"],
    ["id" => 82, "name" => "tutu"],
    ["id" => 12, "name" => "tototo"]
];

$array2 = [
    "45" => ["status" => false], 
    "50" => ["status" => true], 
    "31" => ["status" => true],
    "82" => ["status" => false],
    "12" => ["status" => true]
];

$result = [];
foreach($array1 as $arrayEl) {
    $id = $arrayEl['id'];

    if($array2[$id]['status'] === true) {
        $result[] = $arrayEl;
    }
}

var_dump($result);

注意：我们不是在修改原始内容，而是创建一个新的结果数组。您可能要根据阵列包含/可能不包含的键添加其他isset检查。

Answer 3

请尝试使用此代码。

<?php
$array1 = [
    ["id" => 45, "name" => "toto"],
    ["id" => 50, "name" => "tata"],
    ["id" => 31, "name" => "titi"],
    ["id" => 82, "name" => "tutu"],
    ["id" => 12, "name" => "tototo"]
];

$array2 = [
    "45" => ["status" => false], 
    "50" => ["status" => true], 
    "31" => ["status" => true],
    "82" => ["status" => false],
    "12" => ["status" => true]
];

foreach($array1 AS $key => $value){
    if(!$array2[$value['id']]['status']){
        unset($array1[$key]);
    }

}

echo "<pre>";
print_r($array1);

?>

从第一个数组中找到键，并使用true或false值将其取消设置。

输出：

Array
(
    [1] => Array
        (
            [id] => 50
            [name] => tata
        )

    [2] => Array
        (
            [id] => 31
            [name] => titi
        )

    [4] => Array
        (
            [id] => 12
            [name] => tototo
        )

)

Answer 4

您可以使用array_walk

$res=[];
array_walk($array1, function(&$v,$k) use (&$res,$array2){
  ($array2[$v['id']]['status'] == 1) ? ($res[] = $v): '';
});

Live Demo

Answer 5

这里还有一个解决方案，

array_walk($array1, function(&$item,$key) use(&$array1, $array2){
    if(!$array2[$item['id']]['status'])  // checking status if false
        unset($array1[array_search($item['id'], array_column($array1,'id'))]); // then unset
});
print_r($array1);

array_walk —将用户提供的函数应用于数组的每个成员
array_search —在数组中搜索给定值，如果成功，则返回第一个对应的键
array_column —从输入数组的单个列中返回值

工作demo。

Answer 6

这可能是可读性最低的解决方案:-)

Array_intersect和array_column也可以完成工作。

我将两个数组都关联为id，然后使用array_intersect_key获得真实值。

InternetDomainName.from("test.blogspot.com").topDomainUnderRegistrySuffix() -> blogspot.com

https://3v4l.org/QVoI5

Answer 7

$array1 = [
    ["id" => 45, "name" => "toto"],
    ["id" => 50, "name" => "tata"],
    ["id" => 31, "name" => "titi"],
    ["id" => 82, "name" => "tutu"],
    ["id" => 12, "name" => "tototo"]
];

$array2 = [
    "45" => ["status" => false],
    "50" => ["status" => true],
    "31" => ["status" => true],
    "82" => ["status" => false],
    "12" => ["status" => true]
];

foreach ($array1 as $tocheck) {

    if ($array2[$tocheck['id']]['status']) {
        $new[] = $tocheck;
    }
}

print_r($new);

PHP使用另一个数组删除数组中的数组

7 个答案: