Question

我有两个不同的表。我将它们都归为一体。两者都有两列。因此，我想通过将两个表中的相同字段分组来收集这些字段中的数据。

示例；

mytable

salarytype    salary
Asalarytype   1000
Bsalarytype   2000
Csalarytype   3000

mytable2

salarytype    salary
Asalarytype   100
Bsalarytype   100
Csalarytype   100

我想要：1000 + 100 = 1100，2000 + 100 = 2100，3000 + 100 = 3100 ...

SELECT salarytype
,SUM(salary) FROM mytable GROUP BY salarytiype


SELECT salarytype
,SUM(salary) FROM mytable2 GROUP BY salarytiype

我想要达到的结果 ;

salarytype    totalsalary
Asalarytype    1100
Bsalarytype    2100
Csalarytype    3100
.
.
.

Answer 1

试试这个-

SELECT salarytype,SUM(Salary) 
FROM
(
    SELECT salarytype,Salary FROM MyTable
    UNION ALL
    SELECT salarytype,Salary FROM MyTable2
)A
GROUP BY salarytype

Answer 2

select salarytype,
       salary+(select salary from mytable2 where mytable2.salarytype== mytable.salarytype)
from mytable;

Answer 3

这应该给您想要的结果-

WITH CTE AS 
(
    SELECT salarytype,
           salary 
    FROM MyTable

    UNION ALL

    SELECT salarytype,
           salary 
    FROM  MyTable2
)
SELECT salarytype,
       SUM(salary)
FROM CTE       
GROUP BY salarytype

Answer 4

我认为您的表具有重复的值：因此您可以这样做

select distinct t1.salarytype, sum(t1.salary) from
(
select salarytype, sum(salary) from  mytable GROUP BY salarytype
UNION ALL
select salarytype, sum(salary) from  mytable2 GROUP BY salarytype
) t1
group by t1.salarytype, orderby t1.salarytype

##Hope this will resolve your problem, you can use distinct, to remove 
duplicates

通过将数据分组到不同的表中来收集数据？

4 个答案: