Question

laravel调试器向我显示此错误：

特质方法启动尚未应用，因为与App \ User上的其他特征方法存在冲突

如果我删除了其中一种特质，Uuids或Entrust，则不会显示错误。但是我都需要它们。那我该如何解决呢？'

我正在使用laravel 5.8

谢谢！

namespace App;
use Zizaco\Entrust\Traits\EntrustUserTrait;
use Illuminate\Foundation\Auth\User as Authenticatable;

class User extends Authenticatable
{

    use Uuids;
    use EntrustUserTrait;

}

特质Uuid

   <?php
namespace App;

use Webpatser\Uuid\Uuid;

trait Uuids
{
    /**
     * Boot function from laravel.
     */
    protected static function boot()
    {
        parent::boot();
        static::creating(function ($model) {
            $model->{$model->getKeyName()} = Uuid::generate(5,'test', Uuid::NS_DNS);
        });
    }
}

我认为这与启动功能有关

Answer 1

<?php
namespace App;

use Webpatser\Uuid\Uuid;

trait Uuids
{
    /**
     * Boot function from laravel.
     */
    protected static function bootUuids()
    {
        static::creating(function ($model) {
            $model->{$model->getKeyName()} = (string) Uuid::generate(4);
        });
    }
}

参考：SQLSTATE[42S01]: Base table or view already exists or Base table or view already exists: 1050 Table

双启动功能导致特征共谋

1 个答案: