我正在尝试绘制以下数据
+-----------+------+------+
| Duration | Code | Seq. |
+-----------+------+------+
| 116.15 | 65 | 1 |
| 120.45 | 65 | 1 |
| 118.92 | 65 | 1 |
| 7.02 | 66 | 1 |
| 73.93 | 66 | 2 |
| 117.53 | 66 | 1 |
| 4.4 | 66 | 2 |
| 111.03 | 66 | 1 |
| 4.35 | 66 | 1 |
+-----------+------+------+
我的代码为:
x1 = df.loc[df.Code==65, 'Duration']
x2 = df.loc[df.Code==66, 'Duration']
kwargs = dict(alpha=0.5, bins=10)
plt.hist(x1, **kwargs, color='k', label='Code 65')
plt.hist(x2, **kwargs, color='g', label='Code 66')
我理想地在y轴上想要的是Seq
的数量。对应于x轴上的不同Durations
。但是现在,我只得到y上Durations
的计数。我该如何纠正?
答案 0 :(得分:0)
您可以使用熊猫对“ x”值进行分箱,然后使用条形图。
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame({'Duration':[116.15, 120.45,118.92,7.02,73.93, 117.53, 4.4, 111.03, 4.35]})
df['Code'] = [65,65,65,66,66,66,66,66,66]
df['Seq.'] = [1,1,1,1,2,1,2,1,1]
df
Duration Code Seq.
0 116.15 65 1
1 120.45 65 1
2 118.92 65 1
3 7.02 66 1
4 73.93 66 2
5 117.53 66 1
6 4.40 66 2
7 111.03 66 1
8 4.35 66 1
df['bin'] = pd.cut(df['Duration'],10, labels=False)
df
Duration Code Seq. bin
0 116.15 65 1 9
1 120.45 65 1 9
2 118.92 65 1 9
3 7.02 66 1 0
4 73.93 66 2 5
5 117.53 66 1 9
6 4.40 66 2 0
7 111.03 66 1 9
8 4.35 66 1 0
x1 = df.loc[df.Code==65, 'bin']
x2 = df.loc[df.Code==66, 'bin']
y1 = df.loc[df.Code==65, 'Seq.']
y2 = df.loc[df.Code==66, 'Seq.']
plt.bar(x1, y1)
plt.bar(x2, y2)
plt.show()