Question

使用以下代码更改视图范围，我将渲染所有事件，但是在某些天范围内，事件将不会渲染。

在接下来的几天范围内-18、19、20或21天，事件将不会呈现，否则对于所有类型的范围都可以。

检查以下对象属性：

$('#fullcalendar_scheduler').fullCalendar('getView').timeBodyScroller.canvas.width

我得到--> "",而不是正宽度...

有什么主意吗？是否存在已知问题？

$('#fullcalendar_scheduler').fullCalendar('option', 'visibleRange', {
        start: new Date(startDate).yyyymmdd(),
        end: dateAdd(startDate, currentDurationCount, $('#zoom-scale-selector').val()).yyyymmdd(),
});

以下函数获取开始和结束日期，我还将发布dateAdd函数：

function updateTimelineDuration(start_date, end_date) {
  if (typeof start_date === 'undefined' || start_date === null || start_date.length == 0) {
    start_date = $.trim($("#start_date").val()).substring(0, 10);
  }

  // If we have no 'start_date', from any source, don't do anything
  if (typeof start_date === 'undefined' || start_date === null || start_date.length == 0) {
    return;
  }

  var startDate = new Date(start_date);

  if (typeof end_date === 'undefined' || end_date === null || end_date.length == 0) {
    end_date = dateAdd(startDate, currentDurationCount - 1, $('#zoom-scale-selector').val());
  }

  var endDate = new Date(end_date);

  var conversionDivisor;
  switch ($('#zoom-scale-selector').val()) {
    case 'month':
        // TODO: Fix me
        // 1 month (30 days) = 2592000000 ms
        conversionDivisor = (1000 * 60 * 60 * 24 * 30);
        break;
    case 'week':
        // 1 week = 604800000 ms
        conversionDivisor = (1000 * 60 * 60 * 24 * 7);
        break;
    case 'day':
    default:
        // 1 day =  86400000 ms
        conversionDivisor = (1000 * 60 * 60 * 24);
  }

  currentDurationCount = Math.round((endDate - startDate) / conversionDivisor) + 1;
  if (currentDurationCount < 1) { currentDurationCount = 1; }

  // Adjust timeline    
  $('#fullcalendar_scheduler').fullCalendar('changeView', 'timeline', new Date(startDate).yyyymmdd());
  $('#fullcalendar_scheduler').fullCalendar('option', 'visibleRange', {
    start: new Date(startDate).yyyymmdd(),
    end: dateAdd(startDate, currentDurationCount, $('#zoom-scale-selector').val()).yyyymmdd(),
  });
  $('#fullcalendar_scheduler').fullCalendar('render');
  // Update zoom-text
  $('#zoom-text').text(currentDurationCount);
}

这是dateAdd函数：

function dateAdd(date, interval, units) {
    var ret = new Date(date); // don't change original date
    var checkRollover = function () { if (ret.getDate() != date.getDate()) ret.setDate(0); };
    switch (units.toLowerCase()) {
        case 'year': ret.setFullYear(ret.getFullYear() + interval); checkRollover(); break;
        case 'quarter': ret.setMonth(ret.getMonth() + 3 * interval); checkRollover(); break;
        case 'month': ret.setMonth(ret.getMonth() + interval); checkRollover(); break;
        case 'week': ret.setDate(ret.getDate() + 7 * interval); break;
        case 'day': ret.setDate(ret.getDate() + interval); break;
        case 'hour': ret.setTime(ret.getTime() + interval * 3600000); break;
        case 'minute': ret.setTime(ret.getTime() + interval * 60000); break;
        case 'second': ret.setTime(ret.getTime() + interval * 1000); break;
        default: ret = undefined; break;
    }
    return ret;
}

在特定日期范围内，事件将不会呈现

0 个答案: