Question

如何仅对“分组依据”求和而不在何处？

编辑：

如何绑定此内容：

SELECT SUM(sent) FROM cars GROUP BY model_name

到（无处）

良好的SQL：

SELECT *
FROM cars 
WHERE status in(0, 1) 
GROUP BY model_name 
HAVING is_ref = 0

Answer 1

这应该是您所追求的。只需选择要分组的列，然后按该列分组即可。另外，由于您不聚合is_ref，因此可以将其插入where子句中。

SELECT model_name, sum(sent) as total FROM cars WHERE status 
in(0, 1) GROUP BY model_name having is_ref=0

Answer 2

这是一种方法-

var companyFilter = {
$schema: "http://powerbi.com/product/schema#basic",
target: {
table: "Company",
column: "Company ID"
},
operator: 'In',
values: [1]
};

Answer 3

您在寻找这样的东西吗？

SELECT model_name,
SUM
(
    CASE 
        WHEN (status IN(0, 1) AND is_ref = 0)  THEN sent 
        ELSE 0 
    END
) [Total]
FROM cars 
GROUP BY model_name

仅按[编辑]选择和功能组

3 个答案: