Question

create function myfn (in tbl (how to define the table input))
as 
return set of <some type>
begin 
 return query AS
 select concat(id,name)  
 from test_tbl 
 where id in (select id from in_tbl);

end;

现在我想将此表作为输入argtype传递给函数。

select * from myfn(<pass the table - test_tbl>);

如何声明表类型输入参数？如何用表输入调用此函数？

    public async Task FileWriteAsync(string text)
    {
        string file = @"uid.txt";
        using (FileStream sourceStream = new FileStream(file, FileMode.Append, FileAccess.Write, FileShare.None, bufferSize: 4096, useAsync: true))
        using (StreamWriter f = new StreamWriter(sourceStream))
        {
            await f.WriteLineAsync(text);
        }
    }
    public void ExFile(int line)
    {

        var uid = Regex.Match(txt_ListUID.Lines[line], @"c_user=(.*?);").Groups[1].ToString().Trim();
        string text = uid + "|zxzxzx";
        _ = FileWriteAsync(text)
    }

Answer 1

您可以使用类型regclass并建立动态查询

create or replace function myfn (in tbl regclass)

returns TABLE(id INT)
as  $$
begin 

RETURN QUERY EXECUTE format('select id 
 from test 
 where id in (select id from %s)',tbl);

end 
$$  LANGUAGE plpgsql;

您使用

调用它

select * from myfn('mytablename');

如何将表作为argtype传递给postgres函数？

1 个答案: