我正在尝试从文件中读取两个自己的数据类型'BoardEdge'的列表。当我尝试运行代码时,出现异常:
“ Main.hs:Prelude.read:无解析”
我怀疑我在负责验证输入(validateInput)的函数上得到此信息。当我在ghci中尝试此功能时,插入两个BoardEdge'objects'效果很好,并给出True。
任何人都可以向我提供建议我做错了什么以及如何解决该问题?
数据类型:
data Field = Empty | Black | Yellow deriving (Eq, Ord, Enum, Show, Read)
data BoardEdge = BoardEdge { colRow :: [[(Field, Int)]]} deriving (Read, Eq, Ord, Show)
Main.hs
main :: IO()
main = do
args <- getArgs
input <- loadInput args
putStrLn "Puzzle input loaded:"
putStrLn input
let parsedInput = parseInput input
if (validateInput parsedInput)
then putStrLn "Input is valid."
else error "Input invalid!"
-- asks for path and reads input file
loadInput :: [String] -> IO String
loadInput [] = getPath >>= readFile where
getPath = do
putStrLn "Provide path to puzzle input file:"
getLine
loadDefinition (a:_) = readFile a
-- get valid data from input file
parseInput :: String -> (B.BoardEdge,B.BoardEdge)
parseInput d = parseInput' $ lines d where
parseInput' (columns: rows :_) =
(read columns, read rows)
Board.hs中导入的验证功能合格为B:
validateInput :: (B.BoardEdge,B.BoardEdge) -> Bool
validateInput (columns, rows) = rowColEq where
rowColEq = countBlocks columns == countBlocks rows
-- function that counts total quantity of colored blocks
countBlocks :: (B.BoardEdge)-> Int
countBlocks (B.BoardEdge colRow) = countBlocks' $ concat colRow where
countBlocks' [] = 0
countBlocks' (x:xs) = snd x + countBlocks' xs
我的输入文件如下:
[[(Black,2),(Yellow,2),(Black,1)],[(Black,2),(Yellow,1),(Black,3)]]
[[(Black,5)],[(Black,2),(Black,1)],[(Black,2),(Black,2)],[(Black,1),(Black,2)]]
答案 0 :(得分:1)
将您自己的代码段和Fyodor的注释结合在一起:
Prelude> data Field = Empty | Black | Yellow deriving (Eq, Ord, Enum, Show, Read)
Prelude> data BoardEdge = BoardEdge { colRow :: [[(Field, Int)]]} deriving (Read, Eq, Ord, Show)
Prelude> let edge1 = BoardEdge [[(Black,2),(Yellow,2),(Black,1)],[(Black,2),(Yellow,1),(Black,3)]]
Prelude> show edge1
"BoardEdge {colRow = [[(Black,2),(Yellow,2),(Black,1)],[(Black,2),(Yellow,1),(Black,3)]]}"
Prelude> let correctInput = it -- ^^ the above
因此,现在我们知道read
的期望,即show
的期望。与您用作输入的内容相比如何?
Prelude> let myInput = "[[(Black,2),(Yellow,2),(Black,1)],[(Black,2),(Yellow,1),(Black,3)]]"
Prelude> correctInput == myInput
False
或更狡猾:如果您希望默认的read
实例解析您的输入,则您的输入必须是正确的具有数据构造函数和全部的Haskell代码。在这种情况下,需要使用BoardEdge
。