Question

这与此question here关联，我使用了第一个答案，我尝试更改代码，但是由于该示例在变量中包含“ []”，因此它似乎不起作用

我在这里有一个文本文件：

room1North = CP
room1East = CP
room1South = OP
room1West = OP
room2North = OP
room2East = CP
room2South = EP
room2West = OP

我希望Python使用文本文件中的值创建变量，以便Python中的变量“ room1North = CP”

到目前为止，我有以下代码


with open("maze files.txt", "r") as f:
    data = f.readlines()


room1North, room1East, room1South, room1West, room2North, room2Eeast, room2South, room2West  = [d.split('=')[1].split('\n')[0] for d in data]

我收到以下错误：

IndexError: list index out of range

Answer 1

您实际上并不需要单独的变量；您需要一个dict，其键是从文件中读取的。

with open("maze files.txt", "r") as f:
    data = {k:v for k, v in [line.strip().replace(' ', '').split("=") for line in f]}

# data["room1North"] == "CP"
# data["room1East"] == "CP"
# data["room1South"] == "OP"
# etc

Answer 2

我认为使用字典而不是单纯依靠变量会更幸运。

with open("maze files.txt", "r") as f:
    data = f.readlines()

rooms = {}
for i in data:
    currentRoom = i.replace(' ', '').strip().split('=')
    rooms[currentRoom[0]] = currentRoom[1]

剩下的就是像下面这样的字典

print(rooms)
#{'room1North ': ' CP', 'room1East ': ' CP', 'room1South ': ' OP', 'room1West ': ' OP', 'room2North ': ' OP', 'room2East ': ' CP', 'room2South ': ' EP', 'room2 West ': ' OP'}

您可以通过rooms["room1North"]

引用每个房间及其值

Answer 3

将您的代码更改为波纹管

with open("maze files.txt", "r") as f:
    data = f.readlines()

room1North, room1East, room1South, room1West, room2North, room2Eeast, room2South, room2West  = [d.split('=')[1].split('\n')[0] for d in ''.join(data).split('\n')]

在Python中从文本文件创建变量

3 个答案: