Question

Hybris为同一基础商店的用户创建了多个购物车。如何选择每家商店的购物车多于一个的用户？

稍后，我将对他们进行排序并删除最旧的购物车。

Create

Answer 1

使用这个：

select {u.pk}, {b.pk}, count(distinct({c.pk})) 
from {
   user as u 
   join cart as c on {c.user} = {u.pk} 
   join basestore as b on {b.pk} = {c.store}
} 
group by {u.pk}, {b.pk} 
having count(distinct({c.pk})) > 1

Answer 2

如果您使用保存的购物车和报价功能，那么可以考虑通过添加WHERE {c.saveTime} IS NULL AND {c.quoteReference} IS NULL

将其不包括在结果中

select {u.pk}, {b.pk}, count(distinct({c.pk})) 
from {
   user as u 
   join cart as c on {c.user} = {u.pk} 
   join basestore as b on {b.pk} = {c.store}
}

WHERE {c.saveTime} IS NULL AND {c.quoteReference} IS NULL
GROUP BY {u.pk}, {b.pk}
having count(distinct({c.pk})) > 1

更新：

要获取用户的唯一列表：

select {u.pk} 
from {...

Hybris关系型FlexibleSearch选择

2 个答案:

更新：