接口public void displayMenu()
{
System.out.println("A. Option #A");
System.out.println("B. Option #B");
System.out.println("C. Option #C");
System.out.println("D. Option #D");
System.out.println("X. Exit!");
System.out.println();
System.out.println("Please enter your choice:");
}
public void start()
{
displayMenu();
Scanner console = new Scanner(System.in);
String input = console.nextLine().toUpperCase();
System.out.println();
switch (input)
{
case "A": System.out.println("Option #A was selected"); break;
case "B": System.out.println("Option #B was selected"); break;
case "C": System.out.println("Option #C was selected"); break;
case "D": System.out.println("Option #D was selected"); break;
case "X": System.out.println("You chose to Exit"); break;
default: System.out.println("Invalid selection made"); break;
}
}
public void startFor()
{
/*Each of these methods will modify the original start() method, each
*will add a loop of the specific type so that the menu is displayed
*repeatedly, until the last option is selected. When the last option
*is selected, exit the method (i.e. stop the loop).
*/
}
强制org.springframework.web.server.WebFilter#filter返回chain.filter。因此，这只会将完整和/或错误信号转发给链。
让我们考虑2个过滤器filterA和filterB和一个请求。按照我的理解，这应该是这样工作的：
Mono<Void>为什么不让request -> filterA(pre) -> filterB(pre) -> business code
response <- filterA(post) <- filterB(post) <----'
返回chain.filter？
如何在filterA的后期修改响应？