我对如何插入复选框的多个数组数据感到困惑。我遇到了一些代码,但是我不知道如何在我的php代码中实现它们。如何从数据库中的复选框插入多个数据?有人能帮我吗?对此,我真的非常感激。预先谢谢你。
<?php
include ('connect.php');
$sql2 = "SELECT * FROM owner WHERE owner_username ='".$_SESSION['username']."'";
$result2 = mysqli_query($conn,$sql2);
$row = mysqli_fetch_array($result2);
$id = $row['owner_id'];
$sql = "SELECT cat_id,name,gender,health_status,neutered,breed,color,age
FROM cat WHERE owner_fk = '$id'";
$result = $conn-> query($sql);
if ($result-> num_rows > 0) {
while ($row = $result-> fetch_assoc()) {
echo "<tr>";
echo "<td>" .$row ['name']. "</td>";
echo "<td>" .$row ['gender']. "</td>";
echo "<td>" .$row ['health_status']. "</td>";
echo "<td>" .$row ['neutered']. "</td>";
echo "<td>" .$row ['breed']. "</td>";
echo "<td>" .$row ['color']. "</td>";
echo "<td>" .$row ['age']. "</td>";
echo "<td>" ."<input type='checkbox' name= 'check[]' value=''". "
</td>";
echo "</tr>";
}
echo "</table>";
}
else{
echo "0 result";
}
$conn-> close();
?>
这是我的php代码:
<?php
include ('connect.php');
if(isset($_POST['submit']))
{
for($i=0;$i<count($_POST["check"]);$i++)
}
$p_id =$_GET ['sitter'];
$price = $_POST ['price'];
$pickup_date =$_POST ['pickup_date'];
$dropoff_date =$_POST ['dropoff_date'];
$numdays = $_POST ['numdays'];
$total =$_POST ['test'];
$sql2 = "INSERT INTO cat_sitter(sitter_fk,cat_fk, price, date_in,
date_out,total_day, total)VALUES ('$p_id','".$_POST["check"]
[$i]."','$cat_id','$price','$pickup_date','$dropoff_date','$numdays',
'$total')" or die ("Error inserting data into table");
if ($conn->query($sql2) === TRUE) {
echo "<script language='javascript'>alert('Succesfully Book.')
window.location.replace(\"book_page.php\");
</script>";
}else{
echo "error: " . $sql2 . "<br>" . $conn->error;
}
?>
答案 0 :(得分:0)
使用爆破功能
In your case replace $_POST["check"] with implode(',',$_POST["check"]) then it will work fine fine hope so
答案 1 :(得分:0)
而不是爆炸和爆炸。您可以使用将复选框数组转换为JSON并存储在单个字段中。
// Convert Array to JSON String
$checkArray = $_POST["check"];
$checkJSON = json_encode($checkArray);
从数据库中获取其值后,将JSON转换为数组。
// Convert JSON string to Array
//$checkJSON is variable fetched from database
$checkArray = json_decode($checkJSON, true);
print_r($checkArray); // Dump all data of the Array