Question

我试图使用AJAX在JavaScript中调用python脚本，但是，我得到的响应是原始代码。这个想法是从python脚本中将数据写入JSON文件，但是它不能正确地运行脚本并覆盖文件中已有的数据。为什么python在这种情况下不起作用？

PYTHON：

import requests
import json

request_headers = {
    'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
    'Accept-Encoding': 'gzip, deflate',
    'Accept-Language': 'en-US,en;q=0.8',
    'Connection': 'keep-alive',
    'Host': 'stats.nba.com',
    'Upgrade-Insecure-Requests': '1',
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'
}

team = '1610612742'

url = "https://stats.nba.com/stats/commonteamroster/?Season=1999-00&TeamID=" + team

response = requests.get(url, headers = request_headers)

data = response.json()

print (response)

class Player():
    def __init__(self, name, position, height, weight):
        self.name = name
        self.position = position
        self.height = height
        self.weight = weight

objs = []

def run():
    x = 0;
    players = []

    for i in data['resultSets'][0]['rowSet']:
        name = data['resultSets'][0]['rowSet'][x][3]
        position = data['resultSets'][0]['rowSet'][x][5]
        height = data['resultSets'][0]['rowSet'][x][6]
        weight = data['resultSets'][0]['rowSet'][x][7]
        stats = 'Name: ' + name + ' Position: ' + position + ' Height: ' + height + ' Weight: ' + weight
        objs.append(Player(name, position, height, weight))
        x+=1

    return (players)
val = 0
list = run()
data2 = {}
for x in objs:
    data2[val] = x.name + ", " + x.position + ", " + x.height + ", " +x.weight;
    val+=1
    json_data = json.dumps(data2)

with open('data.json', 'w') as outfile:
     json.dump(json_data + "test", outfile)
print (json_data)

HTML：

<!DOCTYPE html>
<html lang="en" dir="ltr">

<head>
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script>
  <script type="text/javascript" src="data.json"></script>

  <meta charset="utf-8">
  <title></title>
</head>

<body>
  <select id="s1">
    <option value="1610612742">Mavericks</option>
    <option value="1610612756">Suns</option>
    <option value="1610612744">Warriors</option>
    <option value="1610612739">Cavaliers</option>
  </select>
  <select id="s2">
    <option value="1999-00">1999-00</option>
    <option value="2000-01">2000-01</option>
    <option value="2001-02">2001-02</option>
    <option value="2002-03">2002-03</option>
  </select>
  <button id="button" onclick="run()"> Send </button>
  <div id="mine">
  </div>
</body>

<script type="text/javascript">

  var json = '';
  var output = "";

  window.onload = function() {
    $.getJSON( "data.json", function(response) {
      json = $.parseJSON (response);
      var count = Object.keys(json).length;

      for (x = 0; x <= count-1; x++) {
        output = output + json[x] + "\n";
        console.log(json[x]);
      }

      document.getElementById("mine").innerText = output;


    });
  }



  function run () {
    var e = document.getElementById("s1");
    var strTeam = e.options[e.selectedIndex].value;
    var e = document.getElementById("s2");
    var strYear = e.options[e.selectedIndex].value;
    var comp = {'Team':[strTeam], 'Year':[strYear]}
    console.log(comp);

    $.ajax({
    type: 'GET',
    data: comp,
    url: 'script.py',
    success: function(response){ 
        alert(response);
              console.log(response);

    }
    });

  }


</script>

</html>

JSON：

"{\"0\": \"Michael Finley, G, 6-7, 215\", \"1\": \"Damon Jones, G, 6-3, 185\", \"2\": \"Steve Nash, G, 6-3, 195\", \"3\": \"Robert Pack, G, 6-2, 190\", \"4\": \"Erick Strickland, G, 6-3, 210\", \"5\": \"Greg Buckner, G, 6-4, 210\", \"6\": \"Cedric Ceballos, F, 6-7, 220\", \"7\": \"Hubert Davis, G, 6-5, 183\", \"8\": \"Gary Trent, F, 6-8, 250\", \"9\": \"Dirk Nowitzki, F-C, 7-0, 237\", \"10\": \"Shawn Bradley, C, 7-6, 263\", \"11\": \"Sean Rooks, C, 6-10, 270\"}"

来自JavaScript的Python调用无法正常运行

0 个答案: