Question

我有下表，我试图计算每个客户在每个评估下的POC数量。

clientId    ProcDate        ProcDesc    
7180        2018-06-13      Assessment
7180        2018-06-13      POC 20
7180        2018-06-13      POC 4b
7180        2018-06-20      POC 20
7180        2018-06-20      POC 4b
7180        2018-06-27      POC 20
7180        2018-06-27      POC 4b
7180        2018-07-04      Assessment
7180        2018-07-04      POC 20
7180        2018-07-04      POC 4b
7180        2018-07-11      POC 20
7180        2018-07-18      POC 20
7180        2018-07-18      POC 4b
7180        2018-09-05      Assessment
7180        2018-09-05      POC 20
7180        2018-09-12      POC 20
7180        2018-09-12      POC 4b
7180        2018-09-19      POC 20
7180        2018-09-19      POC 4b

2584        2018-10-03      Assessment
2584        2018-10-03      POC 20
2584        2018-10-03      POC 4b
2584        2018-11-04      Assessment
2584        2018-11-04      POC 20
2584        2018-11-04      POC 4b
2584        2018-11-11      POC 20
2584        2018-11-18      POC 20
2584        2018-11-18      POC 4b
7585        2018-11-04      Assessment
7585        2018-11-04      POC 20
7585        2018-11-04      POC 4b
7585        2018-11-11      POC 20
7585        2018-11-18      POC 20
7585        2018-11-18      POC 4b
6581        2018-11-04      CommAssessment
6581        2018-11-04      POC 20
6581        2018-11-04      POC 4b
6581        2018-11-11      POC 20

我想得到如下结果。

ClientId    AssessDate      Type            CountPOC
7180        2018-06-13      Assessment      6
7180        2018-07-04      Assessment      5
7180        2018-09-05      Assessment      5
2584        2018-10-03      Assessment      2
2584        2018-11-04      Assessment      5
7585        2018-11-04      Assessment      5
6581        2018-11-04      CommAssessment      3

我无法弄清楚如何计算每次评估下方的POC数量。

SELECT ClientId, ProcDate, ProcDesc
FROM ProcJoins
WHERE ProcDesc] in ('Assessment','POC 20','POC 4b')  
GROUP BY ClientId, ProcDate, ProcDesc
ORDER BY ProcedureDate

Answer 1

这里有2种选择来满足您的需求。

第一个假设每个客户总是以评估开始。

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div class="addDivRandom">
</div>
<button class="addDivBtn" style="display: block;">Add</button>
<button class="bubbleBtn" style="display: block;">Bubble</button>

第二个只是使用范围查询。

WITH CTE AS(
    SELECT *, 
        ROW_NUMBER() OVER( ORDER BY clientId, ProcDate) rn
    FROM ProcJoins
)
SELECT clientId, 
       ProcDate,
       ProcDesc,
       LEAD(rn, 1, t.totalProc) OVER(ORDER BY clientId, rn) - rn - 1
FROM CTE
CROSS JOIN( SELECT COUNT(*) + 1 AS totalProc FROM CTE) t
WHERE ProcDesc = 'Assessment'
ORDER BY clientId DESC, ProcDate;

第三种版本与2005、2008和2008R2版本兼容

WITH CTE AS(
    SELECT *, 
         LEAD(ProcDate, 1, '99990101') OVER(PARTITION BY clientId ORDER BY ProcDate) EndDate
    FROM ProcJoins
    WHERE ProcDesc = 'Assessment'
)
SELECT c.clientId, 
       c.ProcDate,
       c.ProcDesc,
       COUNT(*)
FROM CTE c
JOIN ProcJoins p ON p.ProcDate >= c.ProcDate
                AND p.ProcDate < c.EndDate
                AND p.clientId = c.clientId
WHERE p.ProcDesc <> 'Assessment'
GROUP BY c.clientId, 
       c.ProcDate,
       c.ProcDesc
ORDER BY clientId DESC, ProcDate;

Answer 2

样本数据：

declare @Test table
    (ClientId int, ProcDate date,ProcDesc varchar(20))
insert @Test values
(7180,'2018-06-13','Assessment'),
(7180,'2018-06-13','POC 20'),
(7180,'2018-06-13','POC 4b'),
(7180,'2018-06-20','POC 20'),
(7180,'2018-06-20','POC 4b'),
(7180,'2018-06-27','POC 20'),
(7180,'2018-06-27','POC 4b'),
(7180,'2018-07-04','Assessment'),
(7180,'2018-07-04','POC 20'),
(7180,'2018-07-04','POC 4b'),
(7180,'2018-07-11','POC 20'),
(7180,'2018-07-18','POC 20'),
(7180,'2018-07-18','POC 4b'),
(7180,'2018-09-05','Assessment'),
(7180,'2018-09-05','POC 20'),
(7180,'2018-09-12','POC 20'),
(7180,'2018-09-12','POC 4b'),
(7180,'2018-09-19','POC 20'),
(7180,'2018-09-19','POC 4b'),
(2584,'2018-10-03','Assessment'),
(2584,'2018-10-03','POC 20'),
(2584,'2018-10-03','POC 4b'),
(2584,'2018-11-04','Assessment'),
(2584,'2018-11-04','POC 20'),
(2584,'2018-11-04','POC 4b'),
(2584,'2018-11-11','POC 20'),
(2584,'2018-11-18','POC 20'),
(2584,'2018-11-18','POC 4b'),
(7585,'2018-11-04','Assessment'),
(7585,'2018-11-04','POC 20'),
(7585,'2018-11-04','POC 4b'),
(7585,'2018-11-11','POC 20'),
(7585,'2018-11-18','POC 20'),
(7585,'2018-11-18','POC 4b'),
(1585,'2018-11-04','CommAssessment'),
(1585,'2018-11-04','POC 20'),
(1585,'2018-11-04','POC 4b'),
(1585,'2018-11-11','POC 20'),
(1585,'2018-11-18','POC 20'),
(1585,'2018-11-18','POC 4b')

拟议的“老派”解决方案：
编辑：我忘记了“ ClientId”
Fiddle

select ClientId, AssessDate = ProcDate, [Type] = ProcDesc, CountPOC = (
        select count(*)
        from @Test
        where ProcDesc like 'POC%' --- <> 'Assessment'
            and ClientId = t.ClientId
            and ProcDate >= t.ProcDate
            and ProcDate < isNull((
                    select top 1 ProcDate
                    from @Test
                    where ClientId = t.ClientId
                        and ProcDate > t.ProcDate
                        and ProcDesc not like 'POC%' -- = 'Assessment'
                    order by ProcDate
                    ), getdate())
        )
from @Test t
where t.ProcDesc not like 'POC%' -- = 'Assessment'

Answer 3

另一种可能的方法是定义组并获取计数：

输入：

CREATE TABLE #Data (
    ClientId int, 
    ProcDate date,
    ProcDesc varchar(10)
)
INSERT INTO #Data 
    (ClientId, ProcDate, ProcDesc)
VALUES
    (7180, '20180613',  'Assessment'),
    (7180, '20180613',  'POC 20'),
    (7180, '20180613',  'POC 4b'),
    (7180, '20180620',  'POC 20'),
    (7180, '20180620',  'POC 4b'),
    (7180, '20180627',  'POC 20'),
    (7180, '20180627',  'POC 4b'),
    (7180, '20180704',  'Assessment'),
    (7180, '20180704',  'POC 20'),
    (7180, '20180704',  'POC 4b'),
    (7180, '20180711',  'POC 20'),
    (7180, '20180718',  'POC 20'),
    (7180, '20180718',  'POC 4b'),
    (7180, '20180905',  'Assessment'),
    (7180, '20180905',  'POC 20'),
    (7180, '20180912',  'POC 20'),
    (7180, '20180912',  'POC 4b'),
    (7180, '20180919',  'POC 20'),
    (7180, '20180919',  'POC 4b'),
    (2584, '20181003',  'Assessment'),
    (2584, '20181003',  'POC 20'),
    (2584, '20181003',  'POC 4b'),
    (2584, '20181104',  'Assessment'),
    (2584, '20181104',  'POC 20'),
    (2584, '20181104',  'POC 4b'),
    (2584, '20181111',  'POC 20'),
    (2584, '20181118',  'POC 20'),
    (2584, '20181118',  'POC 4b'),
    (7585, '20181104',  'Assessment'),
    (7585, '20181104',  'POC 20'),
    (7585, '20181104',  'POC 4b'),
    (7585, '20181111',  'POC 20'),
    (7585, '20181118',  'POC 20'),
    (7585, '20181118',  'POC 4b'),
    (6581, '20181104',  'CommAssessment'),
    (6581, '20181104',  'POC 20'),
    (6581, '20181104',  'POC 4b'),
(6581, '20181111',  'POC 20')

声明（如果支持SUM (...) OVER (ORDER BY ...)）

;WITH GroupsCTE AS (
    SELECT 
        ClientId, ProcDate, ProcDesc,
        SUM(CASE WHEN ProcDesc IN ('Assessment', 'CommAssessment') THEN 1 ELSE 0 END) 
        OVER (ORDER BY ClientId, ProcDate, CASE WHEN ProcDesc IN ('Assessment', 'CommAssessment') THEN 0 ELSE 1 END) AS Groups
    FROM #Data
), CountCTE AS (
    SELECT
       ClientId, ProcDate, ProcDesc,
       COUNT(*) OVER (PARTITION BY Groups) AS [Count]
    FROM GroupsCTE      
)
SELECT 
    ClientId, ProcDate, ProcDesc, [Count] - 1
FROM CountCTE
WHERE ProcDesc IN ('Assessment', 'CommAssessment')
ORDER BY ClientId, ProcDate

声明（如果不支持SUM (...) OVER (ORDER BY ...)）

;WITH GroupsCTE AS (
    SELECT 
        d.ClientId, d.ProcDate, d.ProcDesc,
        c.[Group]
    FROM #Data d
    CROSS APPLY(
        SELECT
        SUM(CASE WHEN ProcDesc IN ('Assessment', 'CommAssessment') THEN 1 ELSE 0 END) AS [Group]
        FROM #Data
        WHERE (ClientId = d.ClientId) AND (ProcDate <= d.ProcDate)
    ) c
), CountCTE AS (
    SELECT ClientId, [Group], COUNT(*) - 1 AS [Count]
    FROM GroupsCTE
    GROUP BY ClientId, [Group]
)
SELECT 
    g.ClientId, g.ProcDate, g.ProcDesc,
    c.[Count]
FROM GroupsCTE g
CROSS APPLY (
    SELECT ClientId, [Group], COUNT(*) - 1 AS [Count]
    FROM GroupsCTE
    WHERE (ClientId = g.ClientId) AND ([Group] = g.[Group])
    GROUP BY ClientId, [Group]
) c
WHERE g.ProcDesc IN ('Assessment', 'CommAssessment')
ORDER BY g.ClientId, g.ProcDate, CASE WHEN g.ProcDesc IN ('Assessment', 'CommAssessment') THEN 0 ELSE 1 END, g.ProcDesc

输出：

ClientId    ProcDate    ProcDesc    (No column name)
2584        2018-10-03  Assessment  2
2584        2018-11-04  Assessment  5
6581        2018-11-04  CommAssessment  3
7180        2018-06-13  Assessment  6
7180        2018-07-04  Assessment  5
7180        2018-09-05  Assessment  5
7585        2018-11-04  Assessment  5

计算行中的特定值

3 个答案: