我需要按定义为文本的“优先级”字段对存储分区进行排序,但是我不知道该怎么做。
您愿意帮我吗?
我尝试了bucket_sort,但是ES给出了关于类型的错误,与排序和顺序相同。
这是聚合查询
{
"query": {
[...]
},
"sort": [
{
"priority.keyword": {
"order": "asc"
}
}
],
"aggregations": {
"by_family": {
"terms": {
"field": "familyId",
"size": 25,
"min_doc_count": 1,
"shard_min_doc_count": 0,
"show_term_doc_count_error": false,
"order": [
{
"_count": "desc"
},
{
"_key": "asc"
}
]
},
"aggregations": {
"same_family": {
"top_hits": {
"from": 0,
"size": 1,
"version": false,
"explain": false,
"highlight": {
"pre_tags": [
"<search>"
],
"post_tags": [
"</search>"
],
"fields": {
"title*": {
"type": "unified"
}
}
}
}
}
}
}
}
}
结果示例是:
{
"responses" : [
{
"took" : 13117,
"timed_out" : false,
"_shards" : {
"total" : 10,
"successful" : 10,
"skipped" : 0,
"failed" : 0
},
"hits" : {
"total" : 1754299,
"max_score" : null,
"hits" : [...]
},
"aggregations" : {
"by_family" : {
"doc_count_error_upper_bound" : 40,
"sum_other_doc_count" : 1753462,
"buckets" : [
{
"key" : 39031576,
"doc_count" : 92,
"same_family" : {
"hits" : {
"total" : 92,
"max_score" : 10.636923,
"hits" : [
{
"_index" : "idx5-1554993721115",
"_type" : "_doc",
"_id" : "589403A-333506350",
"_score" : 10.636923,
"_source" : {
"number" : "589403A",
"suggest" : {
"input" : [
"589403A"
]
},
"id" : "589403A-333506350",
"familyRepresentative" : 1,
"familyId" : 39031576,
"countryCode" : "NZ",
"number" : "589403",
"kind" : "A",
"family" : [ ],
"priority" : "20070425", <-------------
"created" : "2019-04-14",
"modified" : null,
"title" : [...],
我想按索引中定义为文本的“优先级”字段对存储桶聚合(asc / desc)进行排序
答案 0 :(得分:0)
您需要定义另一个子聚合(例如max或min,具体取决于您要排序的方式),然后按该指标对父terms
聚合进行排序。请记住,在familyId
的存储桶中,文档的priority
字段可能都具有不同的值,因此在给定的文档字段上对存储桶进行排序没有任何意义,而仅是对汇总值进行排序给定字段的
{
"query": {
[...]
},
"sort": [
{
"priority.keyword": {
"order": "asc"
}
}
],
"aggregations": {
"by_family": {
"terms": {
"field": "familyId",
"size": 25,
"min_doc_count": 1,
"shard_min_doc_count": 0,
"show_term_doc_count_error": false,
"order": [
{
"max_priority": "desc"
}
]
},
"aggregations": {
"max_priority": {
"max": {
"script": "Long.parseLong(doc['priority.keyword'].value)"
}
}
}
}
}
答案 1 :(得分:0)
为简单起见,请尝试以下操作:
'aggs' => [
'by_family' => [
'terms' => [
'field' => 'familyId',
'order' => [ '_term' => 'asc' ]
],
],
]
上面的脚本将重点放在您的familyId
字段上,然后您可以将此处的_term
的值更改为asc
或desc
以相应地更改顺序>