我需要从pipe aggregation返回的结果集中计算存储桶的数量。问题是我的查询在这里使用script selector:
POST visitor_carts/_search
{
"size": 0,
"aggs": {
"visitors": {
"terms": {"field" : "visitor_id"},
"aggs": {
"one_purchase": {
"bucket_selector": {
"buckets_path": {
"nb_purchases": "_count"
},
"script": "params.nb_purchases == 3"
}
}
}
}
}
}
返回类似的内容:
{
"took" : 0,
"timed_out" : false,
"_shards" : {
"total" : 1,
"successful" : 1,
"skipped" : 0,
"failed" : 0
},
"hits" : {
"total" : 5,
"max_score" : 0.0,
"hits" : [ ]
},
"aggregations" : {
"visitors" : {
"doc_count_error_upper_bound" : 0,
"sum_other_doc_count" : 0,
"buckets" : [
{
"key" : "2",
"doc_count" : 3
},
{
"key" : "3",
"doc_count" : 3
}
]
}
}
}
在buckets
键下,我可以看到符合我条件的访客列表(由visitor_id
标识的每个访客必须在visitor_carts
索引中恰好有三个文档),但这不是非常有帮助,因为它应该可以处理成千上万的访客。我正在使用PHP处理结果,从理论上讲,它可以计算结果集,但是对于大量的访问者来说,这并不是最好的主意。有没有一种方法可以只输出doc_count_error_upper_bound
和sum_other_doc_count
旁边的有效存储桶数?汇总统计信息中不包含bucket_count
有点奇怪,因为它似乎非常有用。
或者这可以通过其他方式完成?这个问题是该问题的后续内容:Get user count that made a specific number of purchases
这是我的visitor_carts
映射:
{
"mapping": {
"_doc": {
"dynamic": "false",
"properties": {
"created_dt": {
"type": "date",
"format": "yyyy-MM-dd HH:mm:ss"
},
"order_id": {
"type": "keyword"
},
"visitor_id": {
"type": "keyword"
}
}
}
}
}
答案 0 :(得分:1)
您可以使用Stats Bucket Aggregation来获取存储桶数。
下面是查询的样子。
POST visitor_carts/_search
{
"size": 0,
"aggs": {
"visitors": {
"terms": {
"field" : "visitor_id"
},
"aggs": {
"one_purchase": {
"bucket_selector": {
"buckets_path": {
"nb_purchases": "_count"
},
"script": "params.nb_purchases == 3"
}
}
}
},
"mybucketcount":{
"stats_bucket": {
"buckets_path":"visitors._count"
}
}
}
}
{
"took": 1,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"failed": 0
},
"hits": {
"total": 8,
"max_score": 0,
"hits": []
},
"aggregations": {
"visitors": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "2",
"doc_count": 3
},
{
"key": "3",
"doc_count": 3
}
]
},
"mybucketcount": {
"count": 2, <---- This is the count you are looking for
"min": 3,
"max": 3,
"avg": 3,
"sum": 6
}
}
}
让我知道这是否有帮助!