Question

我需要匹配在数据库中获取的用户名和密码。现在的问题是我无法匹配用户名和密码，如下图所示：

下面是我的代码：

HTML

    <body>  
          <div class="container box">  
           <div class="form-group">  
            <h3 align="center">Live Username Available or not By using PHP Ajax Jquery</h3><br />  
            <label>Enter Username</label>  
            <input type="text" name="username" id="username" class="form-control" />
            <input type="password" name="password" id="password" class="form-control" />


            <span id="availability"></span>
            <br /><br />
            <button type="button" name="register" class="btn btn-info" id="register" disabled>Register</button>
            <br />
           </div>  
           <br />  
           <br />  
          </div>  
  </body>

jQuery脚本-这是在用户名和密码匹配或不匹配之后显示匹配可用性的地方

<script>  
 $(document).ready(function(){  
  $('#username, #password').blur(function(){

    var username = $('#username').val();
    var password = $('#password').val();

     $.ajax({
      url:'check.php',
      method:"POST",
      data:{user_name:username, password:password},
      success:function(data)
      {
        console.log(data);
       if(data != '0')
       {
        $('#availability').html('<span class="text-danger">Username and Password not Match</span>');
        $('#register').attr("disabled", true);
       }
       else
       {
        $('#availability').html('<span class="text-success">Username and Password Available</span>');
        $('#register').attr("disabled", false);
       }

      }

     })

  });
 });  
</script>

check.php-数据库连接和查询

  <?php  
    //check.php  
    $connect = mysqli_connect("localhost", "username", "", "dbname"); 
    if(isset($_POST["user_name"], $_POST["password"]))
    {
     $username = mysqli_real_escape_string($connect, $_POST["user_name"]);
     $password = mysqli_real_escape_string($connect, $_POST["password"]);
     $query = "SELECT * FROM admin WHERE username = '".$username."' AND password = '".$password."' ";
     $result = mysqli_query($connect, $query);
     echo mysqli_num_rows($result);
    }
 ?>

Answer 1

我认为您的条件在客户端脚本中是错误的。如果用户名和密码匹配，则它将返回大于0的值。在这种情况下，您的代码应为

success:function(data)
  {
    console.log(data);
    if(data == 0)
    {
      $('#availability').html('<span class="text-danger">Username and Password not Match</span>');
      $('#register').attr("disabled", true);
    } 
    else
    {
      $('#availability').html('<span class="text-success">Username and Password Available</span>');
      $('#register').attr("disabled", false);
    }
   }

Answer 2

最低分 这是OP也存在的问题的解决方案。请参阅主线程注释。谢谢。

只需将POST值包装到md5 function中即可。

$password = md5(mysqli_real_escape_string($connect, $_POST["password"]));

或可以尝试使用MD5 in database。

$query = "SELECT * FROM admin WHERE username = '".$username."' AND password = MD5('".$password."') ";

然后，密码哈希应等于数据库哈希。

Answer 3

您可以尝试以下操作：

loginCheck(){

    if(this.form.valid){
        const userCategory = this.form.value.userCategory;
      const userName = 'admin'; //this.form.value.userName;
      const passwd = 'admin'; //this.form.value.passwd;

      console.log(userCategory, userName, passwd);

      this._storage.set('IS_LOGGED_IN', true);
      this._authService.isLoggedIn = true;

      this.router.navigate(['admin']);
    }
  }

匹配在数据库中获取的用户名和密码-Jquery

3 个答案: