Question

MOXy传统上是XML到Object的对象，但是它也可以通过MoxyJsonProvider生成JSON。 MOXy还具有通过XPath映射在1-1转换之外映射到XML的工具。您还可以使用此工具来修改JSON输出吗？我对此表示怀疑，但一位同行问我这个问题。

现在，我可以通过FasterXML Jackson通过一些技术来实现这一点，例如为我想要从另一个实体获得的特定属性创建@JsonProperty或通过使用我要创建嵌套JSON对象的字段填充地图。

// XML Input
// I don't have this file. I'll try to generate it based on the code but the meat and bones of the question is in the transformation via
File xmlInput = new File(input.xml);

// Processs the XML
JAXBContext context = JAXBContext.newInstance("model");
Unmarshaller unmarshaller = context.createUnmarshaller();
CustomerImpl customerImpl =
(CustomerImpl) unmarshaller.unmarshal(xmlInput);

// Build the Customer Object
Customer customer = new Customer();

// Build the Address Object
ContactInfoImpl contactInfoImpl = customerImpl.getContactInfo();
if(null != contactInfoImpl) {
     AddressImpl addressImpl = customerImpl.getAddress();
     if(null != addressImpl) {
          Address address = new Address();
          customer.setAddress(address);
          address.setStreet(addressImpl.getStreet());
     }
}

Customer.java

@XmlRootElement
public class Customer {

   @XmlPath("contact-info/address")
   private Address address;
}

这将生成：

<customer>
     <contact-info>
          <address>
               <street>123 Any Street</street>
          </address>
     </contact-info>
</customer>

这也可以用于生成修改后的JSON映射吗？即我可以使用它来将嵌套的JSON对象折叠到字段中或将字段包装到嵌套的JSON对象中吗？例子

{
  "street" : "123 Any Street"
}

通过“ XMLPath”注释进行了修改：

Customer.java

@XmlRootElement
public class Customer {

   @XmlPath("address")
   private String address;
}

{
  "address" : { 
    "street" : "123 Any Street"
  }
}

MOXy的“ Meet-In-The-Middle”工具可以用于JSON映射吗？

0 个答案: