前1个结果选择查询

Question

我遇到以下错误

  

”错误号：1064

     

您的SQL语法有错误；检查手册   对应于您的MySQL服务器版本以使用正确的语法   接近'1 Sum（picker_sign_out_sheet.lines_on_order）AS LINES，   在第1行的staff.staff_name AS PICKER'

我不知道从哪里开始，希望有所帮助

("SELECT TOP 1 Sum(picker_sign_out_sheet.lines_on_order) AS LINES, staff.staff_name AS PICKER
FROM picker_sign_out_sheet INNER JOIN staff ON picker_sign_out_sheet.staff_name = staff.staff_id
WHERE (((picker_sign_out_sheet.finish_date)=Date()))
GROUP BY staff.staff_name
ORDER BY Sum(picker_sign_out_sheet.lines_on_order) DESC");

我希望得到1个结果，显示哪个用户的lines_on_order总数最高。

任何帮助都是很棒的

Answer 1

TOP 1不是MySQL语法

正确的查询应该是

SELECT Sum(picker_sign_out_sheet.lines_on_order) AS LINES, staff.staff_name AS PICKER
FROM picker_sign_out_sheet INNER JOIN staff ON picker_sign_out_sheet.staff_name = staff.staff_id
WHERE (((picker_sign_out_sheet.finish_date)=Date()))
GROUP BY staff.staff_name
ORDER BY Sum(picker_sign_out_sheet.lines_on_order) DESC
LIMIT 1

Answer 2

请删除顶部01并全部获得$ query-> row_array（）;
这只会返回一个值top