您将如何构建关系数据库中的数据?当我更新数据库时,我想在两个表中添加一个相应的批号(batch_no),以便可以链接数据。我该怎么办?
第一个表(可能需要拆分????)是数据上传的分类结果。
+--------------+-----------+--------+----------+---------+----------+
| | precision | recall | f1-score | support | batch_id |
+--------------+-----------+--------+----------+---------+----------+
| | | | | | |
| positive | 0.56 | 0.7 | 0.62 | 1034 | 1 |
| negative | 0.96 | 0.94 | 0.95 | 8966 | 1 |
| | | | | | |
| micro avg | 0.91 | 0.91 | 0.91 | 10000 | 1 |
| macro avg | 0.76 | 0.82 | 0.79 | 10000 | 1 |
| weighted avg | 0.92 | 0.91 | 0.92 | 10000 | 1 |
| | | | | | |
| positive | 0.56 | 0.7 | 0.62 | 1034 | 2 |
| negative | 0.96 | 0.94 | 0.95 | 8966 | 2 |
| | | | | | |
| micro avg | 0.91 | 0.91 | 0.91 | 10000 | 2 |
| macro avg | 0.76 | 0.82 | 0.79 | 10000 | 2 |
| weighted avg | 0.92 | 0.91 | 0.92 | 10000 | 2 |
+--------------+-----------+--------+----------+---------+----------+
第二张表是很多评论。
+----+------------+-----------+--------+----------+
| id | reviewtext | predicted | actual | batch_id |
+----+------------+-----------+--------+----------+
| 1 | blah blah | pos | neg | 1 |
| 2 | blah blah | pos | pos | 1 |
| 3 | blah blah | neg | neg | 1 |
| 4 | blah blah | pos | neg | 2 |
| 5 | blah blah | pos | pos | 2 |
| 6 | blah blah | neg | neg | 2 |
+----+------------+-----------+--------+----------+
我已经尝试过使用复合键,并将第一个数据库分为正数和负数,然后有一个主键来更新评论表,但是我似乎无法弄清它。
答案 0 :(得分:0)
您的“分类”表应将“ id”列作为主键:
---+--------------+-----------+--------+----------+---------+
id| | precision | recall | f1-score | support |
---+--------------+-----------+--------+----------+---------+
1| | | | | |
2| positive | 0.56 | 0.7 | 0.62 | 1034 |
3| negative | 0.96 | 0.94 | 0.95 | 8966 |
4| | | | | |
5| micro avg | 0.91 | 0.91 | 0.91 | 10000 |
6| macro avg | 0.76 | 0.82 | 0.79 | 10000 |
7| weighted avg | 0.92 | 0.91 | 0.92 | 10000 |
---+--------------+-----------+--------+----------+---------+
然后在“评论”表上,为“分类”表创建外键:
---+------------+-----------+--------+------------------+
id| reviewtext | predicted | actual | classification_id|
---+------------+-----------+--------+------------------+
1| blah blah | pos | neg | 1 |
2| blah blah | pos | pos | 2 |
3| blah blah | neg | neg | 3 |
---+------------+-----------+--------+------------------+
现在,如果要在一个查询中访问两个表中的数据,则可以JOIN
个表:
SELECT
*.t1,
*.t2
FROM classification t1
LEFT JOIN reviews t2
ON (t1.id = t2.classification_id)
如果您需要有关Django ORM的帮助,请使用您的模型更新您的帖子,并告诉我。